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Art [367]
3 years ago
7

Work out the value of 22 - 2y when

Mathematics
1 answer:
stealth61 [152]3 years ago
6 0

Answer:

2

Step-by-step explanation:

22 - 2y

= 22 - 2 ( 10 )

= 22 - 20

= 2

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Jason eats 10 ounces of candy in 5 days.
svetoff [14.1K]

Answer:

a) 0,125 pounds/day

b) 8 days to eat one pound

Step-by-step explanation:

If Jason eats 10 ounces of candy in 5 days it meas that he eats 2 onces in a day

Then                       16 ounces = 1 pound  

                                 2 ounces ⇒    x

x = 2/16  ⇒            x =1/8                  ⇒ x = 0,125  pounds per day

Now he eats 2 ounces per day to eats 1 poun (16 ounces) he needs 8 days

6 0
3 years ago
Read 2 more answers
What is the measure of 7 shown in the diagram below?
Korolek [52]

Answer:

c  

Step-by-step explanation:

5 0
3 years ago
An account had an initial deposit made and then interest was applied once a year at a fixed rate. The amount of money, in dollar
Nat2105 [25]
Amount in compound interest = p(1 + r/t)^nt where p is the initial deposit, r = rate, t = number of compunding in a period and n = period.

Here, Amount after t years = 103(1.02)^t
i.e. 1 + r = 1.02
r = 1.02 - 1 = 0.02
Therefore, annual interest rate = 0.02 x 100 = 2%
8 0
3 years ago
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Mercedes receives a $25 gift card for downloading music and wants to determine how many songs she can purchase. Each downloaded
Naddik [55]
Your answer is A. he can get 19.37 songs because 25 divided by 1.29 is 19.37 (mark me as brainliest, this answer is 100% accurate)
4 0
3 years ago
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In a given year, the average annual salary of a NFL football player was $189,000 with a standard deviation of $20,500. If a samp
nika2105 [10]

Answer:

15.15% probability that the sample mean will be $192,000 or more.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 189000, \sigma = 20500, n = 50, s = \frac{20500}{\sqrt{50}} = 2899.14

The probability that the sample mean will be $192,000 or more is

This is 1 subtracted by the pvalue of z when X = 192000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{192000 - 189000}{2899.14}

Z = 1.03

Z = 1.03 has a pvalue of 0.8485.

1-0.8485 = 0.1515

15.15% probability that the sample mean will be $192,000 or more.

7 0
3 years ago
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