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2 years ago

PLEASE HELPPPPP!!!

Mathematics

2 answers:

Vladimir [108]2 years ago

8 0

Step-by-step explanation:

Slope-intercept form: y = mx + c

We have m = 1/4. Since it passes through the

point (-4, 2), => When x = -4, y = 2.

=> (2) = (1/4)(-4) + c, 2 = c - 1, c = 3.

Hence the equation is y = x/4 + 3.

maw [93]2 years ago

8 0

Answer:

Y = 1/4x + 3

Step-by-step explanation:

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In the trapezoid, what is the measure of 1?

Setler [38]

Answer:

Step-by-step explanation:

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2 years ago

If D varies directly with t and D is 105 when t is 3, find D when t is 8. 35 280 840

drek231 [11]

Answer:

280

Step-by-step explanation:

D = kt

105 = 3k

k = 35

D = 35t

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3 years ago

Read 2 more answers

BC = Round your answer to the nearest hundredth. B 50° 7

Brrunno [24]

Answer:

BC = 5.87

Step-by-step explanation:

Reference angle = 50°

Side Opposite to reference angle = 7

Adjacent side = BC = ?

Apply trigonometric function, TOA, thus:

Tan 50 = Opp/Adj

Tan 50 = 7/BC

BC × Tan 50 = 7

BC = 7/Tan 50

BC = 5.87369742 ≈ 5.87 (nearest hundredth)

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2 years ago

write the equation of a line that is parallel to y = - 3/2 x -1 and that passes through the point (4,6)

maria [59]

Answer:

Step-by-step explanation:Given Equation of line has slope m=-3/2

So the line passing through (4,6) has the same slope because both are parallel

From slope intercept form we have

y-y1=m(x-x1)

y-6=-3/2(x-4)

y-6=-3/2x +3/2(4)

y=-3/2x+12

2y=-3x+24

3 0

3 years ago

The power generation plant of a ship is outfitted with two identical diesel-generator sets. One single set running stand-alone c

dem82 [27]

Answer:

probability of an electric power outage shipboard is 0.075 or 7.5 %

Step-by-step explanation:

Given the data in the question;

Probability of engine malfunction = 25% = 0.25

Probability of generator malfunction = 10% = 0.1

Probability of generator being repaired = 50% = 0.5

probability of an electric power outage shipboard = ?

To get the probability of an electric power outage shipboard, we use the expression;

probability of an electric power outage = 2 $_c_1$ × p( Probability of generator malfunction ) × p( Probability of generator being repaired ) × ( 1 - p( Probability of engine malfunction ) )

so we substitute in our given values;

probability of an electric power outage = 2 × 0.1 × 0.5 × ( 1 - 0.25 )

probability of an electric power outage = 2 × 0.1 × 0.5 × 0.75

probability of an electric power outage = 0.075 or 7.5 %

3 0

2 years ago