Answer:
Mean of sampling distribution = 50
Standard deviation of sampling distribution, = 0.625
Step-by-step explanation:
Given :
Mean, μ = 50
Standard deviation, σ = 5
Sample size, n = 64
The mean of sampling distribution, μxbar = population mean, μ
μxbar = μ
According to the central limit theorem, the sampling distribution converges to the population mean as the sample size increases, hence, , μxbar = μ = 50
Standard deviation of sampling distribution, σxbar = σ/√n
σxbar = 5/√64 = 5 / 8 = 0.625
