The answer is cot² ∅ - csc² ∅ = -1
Referring to Pythagorean identities:
sin² ∅ + cos² ∅ = 1
1+cot² ∅ = csc² ∅
tan² ∅ + 1 = sec² ∅
1+cot² ∅ = csc² ∅
⇒ transposing 1 and csc² ∅ we will have now
cot² ∅ - csc² ∅ = -1
n= smallest integer
n+2= middle integer
n+4= largest integer
n + n + 4 = 36
2n+ 4 = 36
2n=32
n= 16 which means that the smallest integer is 16
then you substitute it into the equation for the largest integer
n+4=20
16, 18, 20 is the answer
Answer: 49
and im a taurus
Step-by-step explanation:
sqrt(2x+1) when x=11
sqrt(2*11+1)
sqrt(22+1)
sqrt(23)
4.79583
to the nearest tenth
4.8
sqrt(4x+1) + sqrt(2x) when x=8
sqrt(4*8+1) + sqrt(2*8)
sqrt(32+1) + sqrt(16)
sqrt(33) + 4
5.7446 +4
9.7446
rounding to the nearest tenth
9.7
