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Naddik [55]
3 years ago
10

Help ASAP I need to get this question correct

Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0

Answer: The answer is NO

Step-by-step explanation:

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HELP ASAP!!!
saul85 [17]
D.(6,3)

because your in put is not the same as any of the other in puts
3 0
3 years ago
At what value of x does graph of the following function f(x) have a vertical asymptote? F(x)= 1/x+3
kirill115 [55]

Answer:

A

Step-by-step explanation:

Given

f(x) = \frac{1}{x+3}

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 3 = 0 → x = - 3 is the vertical asymptote

7 0
3 years ago
What is the answer for 8x+3(x-4)
Alika [10]
The answer would be 11x-12
3 0
3 years ago
Read 2 more answers
Find the greatest common factor of 15x^2y^3 and -18x^3yz <br> The Answer has to be like _x_y_
Daniel [21]

Answer:

The greatest common factor of this would be 3x^2y

Step-by-step explanation:

In order to find this, first find the greatest common factor of the coefficients. Since 3 goes in evenly to both 15 and -18, then we know that it is a common factor.

From there we need to find the number of x's. Since the first term only has 2 x's and the second has 3, we take the lowest number. (x^2)

And since the first term has 3 y's and the second has just 1, we take the lowest number (y).

8 0
3 years ago
Point m is located at 4,-2 what is located 2 units for point m
eimsori [14]

Answer:

None

Step-by-step explanation:

Given

m = (4,-2)

Required

Point 2 units from m

There are 4 possible points 2 units from m and they are:

m' = (4+2,-2) = (6,-2)

m" = (4,-2+2) = (4,0)

m'''= (4-2,-2) = (2,-2)

m'''' = (4,-2-2) = (4,-4)

From the graph, we have:

A = (4,2)

B = (-4,2)

C = (2,-3)

None of the points is 2 units from m

7 0
2 years ago
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