Answer:
50.24 (unit squared! cm2, m2, etc.)
Step-by-step explanation:
Area is: Pi x r^2
3.14 x 4^2 = 3.14 x 16 = 50.24
Check the picture below.
so we know the radius of the semicircle is 2 and the rectangle below it is really a 4x4 square, so let's just get their separate areas and add them up.
![\stackrel{\textit{area of the semicircle}}{\cfrac{1}{2}\pi r^2}\implies \cfrac{1}{2}(\stackrel{\pi }{3.14})(2)^2\implies 3.14\cdot 2\implies 6.28 \\\\\\ \stackrel{\textit{area of the square}}{(4)(4)}\implies 16 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{sum of both areas}}{16+6.28=22.28}~\hfill](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20semicircle%7D%7D%7B%5Ccfrac%7B1%7D%7B2%7D%5Cpi%20r%5E2%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B2%7D%28%5Cstackrel%7B%5Cpi%20%7D%7B3.14%7D%29%282%29%5E2%5Cimplies%203.14%5Ccdot%202%5Cimplies%206.28%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20square%7D%7D%7B%284%29%284%29%7D%5Cimplies%2016%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsum%20of%20both%20areas%7D%7D%7B16%2B6.28%3D22.28%7D~%5Chfill)


- A) 2/10 + 8/100 = <u>0</u><u>.</u><u>2</u><u>8</u>
- B) 13/100 + 4/10 = <u>0</u><u>.</u><u>5</u><u>3</u>
- C) 6/10 + 39/100 = <u>0</u><u>.</u><u>9</u><u>9</u>
- D) 70/100 + 3/10 = <u>1</u>
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<em><u>#</u></em><em><u>carry </u></em><em><u>on </u></em><em><u>learning </u></em><u><</u><u>3</u>
H=-5(t^2 - 16t)
H=-5(t^2 - 16t +64)+320
H=-5(t-8)^2 +320
Vertex is at (8, 320)
The max height is 320 m.
Answer:
2
Step-by-step explanation:
12 + 12 = 24