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GrogVix [38]
2 years ago
14

Determine whether the relation is a function. (1-4), (2, 1), (3, 4), (3, 3). (4, 2)

Mathematics
1 answer:
dimaraw [331]2 years ago
4 0

Answer:

b

Step-by-step explanation:

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Write an explicit formula fo the sequence 7,2,-3,-8,-13.... Then find the 14th term
MrRa [10]

Answer:

The 14th term is -58

Step-by-step explanation:

The formula for an arithmetic sequence is

an = a1+d(n-1)

where a1 is the first term

d is the common difference and

n is the term number

a1 = 7

d = 2-7 = -5

Check -3-2 = -5   so d = -5

an = 7 -5(n-1)

We want the 14th term

a14 = 7 -5(14-1)

a14 = 7 -5(13)

a14 = 7 -65

a14 = -58

6 0
3 years ago
Write a rule y=f(x) that would produce the graph.
katen-ka-za [31]

Answer:

  y = | x+2 | -1

Step-by-step explanation:

The absolute value function is shifted left 2 units and down 1. That makes it ...

  y = abs(x+2) -1

Using the usual symbols for absolute value:

  y = |x+2| -1

_____

The translation transformation is ...

  y = f(x -a) +b

to translate the graph of f(x) right by "a" units and up by "b" units. Here, we have a translation left 2 and down 1, so a=-2, b=-1. The original function is the absolute value function in this case.

5 0
3 years ago
-0.38 written as a fraction is _____.
Marizza181 [45]
<span>-0.38 = -38/100 = -19/50</span>
4 0
2 years ago
Read 2 more answers
The standard deviation of Y is 100. The square root of the sum of the squared residuals divided by n-2 equals 15. Does this sugg
UNO [17]

Answer:

regression fits well for your answer

8 0
2 years ago
Find the generating function for the sequence 1,-2,4,-8, 16, ...
kirill [66]

Answer:

  a(x)=\dfrac{1}{1+2x}

Step-by-step explanation:

The generating function a(x) produces a power series ...

  a(x)=a_0+a_1x+a_2x^2+a_3x^3+\dots

where the coefficients are the elements of the given sequence.

We observe that the given sequence has the recurrence relation ...

  a_0=1;a_n=-2a_{n-1} \quad\text{for n $>$ 0}

This can be rearranged to ...

  a_n+2a_{n-1}=0

We can formulate this in terms of a(x) as follows, then solve for a(x).

\sum\limits^{\infty}_{n=1} {a_{n}x^n} =a(x)-a_0 \quad\text{and}\\\\\sum\limits^{\infty}_{n=1} {2a_{n-1}x^n} =(2x)a(x) \quad\text{so}\\\\\sum\limits^{\infty}_{n=1} {(a_n+2a_{n-1})x^n}=0=a(x)-a_0+2xa(x)\\\\a(x)=\dfrac{a_0}{1+2x}=\dfrac{1}{1+2x}

The generating function is ...

  a(x) = 1/(1+2x)

3 0
2 years ago
Read 2 more answers
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