Question

In the diagram below DE is the midsegment of AABC. Find the length of DE and BC.

Answer 1

Answer:

DE = 5

BC = 10

Step-by-step explanation:

ΔAED is a right triangle with legs of 4 and 6/2 = 3

Use the Pythagorean theorem to find DE

$4^{2} + 3^{2} = DE^{2}$

16 + 6 = 25 = $DE^{2}$

DE = 5

The midsegment of a triangle is 1/2 the length of the corresponding side.

Therefore, BC = 2 DE = 2(5) = 10 = BC