The height of the doorway is 252 inches
Suppose we choose
and
. Then
Now suppose we choose
such that
where we pick the solution for this system such that
. Then we find
Note that you can always find a solution to the system above that satisfies
as long as
. What this means is that you can always find the value of
as a (constant) function of
.
Answer:
A = 1100cm^2
Step by step Explanation:
given the dimensions of width and length of the picture are x+20 by 2x-10 and the frame is a constant 5 cm wider from the edge of the picture to the frame, than the area of the frame is defined as (x+30)(2x)-(x+20)(2x-10) = 30x+200.
If the width is equal to the length which I assume is true if the width is constant.
than x+30=2x, which means x = 30.
if this is true than 30(30)+200 = 1100cm^2
Answer:It would be -4 across and go two up
Step-by-step explanation:
Answer:
The answer to your question is SA = 2419.34 m²
Step-by-step explanation:
Data
a = 11.42 m
side = 11 m
height = 20 m
Formula
SA = 2B + PH
Process
1.- Calculate P
Perimeter = P
P = 7(11)
= 77 m
2.- Calculate B
B = Pa/2
= (77)(11.42)/2
= 879.34/2
= 439.67 m²
3.- Calculate 2B
2B = 2(439.67)
= 879.34 m²
4.- Calculate PH
PH = (77)(20)
= 1540 m²
5.- Calculate SA
SA = 879.34 + 1540
= 2419.34 m²
