3 years ago

Help !!!See question in image.Please show workings .

Mathematics

1 answer:

ella [17]3 years ago

4 0

Answer:

$f(x) = 3 {x}^{2} \\ lim \: \frac{f(x + h) - f(x)}{h} \: \: when \: h - > 0 \\ lim \: \frac{3( x + h)^{2} - 3 {x}^{2} }{h} when \: h - > 0 \\ lim \: \frac{3( {x}^{2} + 2xh + {h}^{2}) - 3 {x}^{2} }{h} when \: h - > 0 \\ \\ lim \: \frac{3 {x}^{2} + 6xh + 3h^{2} - 3 {x}^{2} }{h} when \: h - > 0 \\ lim \: \frac{6xh + 3 {h}^{2} }{h} \: when \: h - > 0 \\lim \frac{6xh}{h} + \frac{3h^{2} }{h}when \: h - > 0 \\ lim \: 6x + 3h \: when \: h - > 0 \\ = 6x + 3(0) \\ = 6x + 0 \\ = 6x \\ \\ or \\ \frac{d(3x^{2}) }{dx} = 2 \times 3x^{2 - 1} \\ = 2 \times 3x^{1} \\ = 2 \times 3x \\ = 6x$

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Joseph has $3.00 in his piggy bank and he adds $0.75 each day. Kelsey has $5.25 in her piggy bank and she spends $0.25 each day.

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Answer:

They will have the same amount of money in their piggy banks when they each reach $6. (4 days for Joseph, 3 for Kelsey.)

Step-by-step explanation:

Joseph has $3.00 and will add $0.75 cents to it each day. So for the first day he will have $3.75. Then, $4.50. Then, $5.25. Then on the fourth day, he will have $6.

Kelsey has $5.25 and will add $0.25 each day. For the first day, she will have $5.50 in her piggy bank. Then, $5.75. Then $6.

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4 years ago

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