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nordsb [41]
2 years ago
14

Christian sets aside $60 per month for daily coffee. McDonalds sells coffee for $1, and The Bean Sprout sells a cup of coffee fo

r $3.Create an equation that represents the combinations of coffee options that allow Christian to stay in his budget.Graph the equation for his budget.Provide 2 combinations that use his entire budget, 1 combination that would be under budget, and 1 combination that would be over his budget.
Mathematics
1 answer:
VladimirAG [237]2 years ago
4 0

Since Christian sets aside $60 per month for daily coffee, and McDonalds sells coffee for $ 1, and The Bean Sprout sells a cup of coffee for $3, to create an equation that represents the combinations of coffee options that allow Christian to stay in his budget and provide 2 combinations that use his entire budget, 1 combination that would be under budget, and 1 combination that would be over his budget, the following linear equation must be proposed:

 

M + BS = 60

2 combinations using the entire budget =

  • 15 McDonalds + 15 The Bean Sprout = 15 + 45 = 60
  • 30 McDonalds + 10 The Bean Sprout = 30 + 30 = 60

1 combination under budget =

  • 15 McDonalds + 10 The Bean Sprout = 15 + 30 = 45

1 combination over budget =

  • 30 McDonalds + 30 The Bean Sprout = 30 + 90 = 120

Learn more in brainly.com/question/14305871

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Answer:

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Step-by-step explanation:

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The exponential probability distribution, with mean m, is described by the following equation:

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The probability that x is lower or equal to a is given by:

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The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The manager of a fast-food restaurant determines that the average time that her customers wait for service is 3.5 minutes.

This means that m = 3.5, \mu = \frac{1}{3.5} = 0.2857

What number of minutes should the advertisement use?

The values of x for which:

P(X > x) = 0.01

So

e^{-\mu x} = 0.01

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\ln{e^{-0.2857x}} = \ln{0.01}

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x = -\frac{\ln{0.01}}{0.2857}

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