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nordsb [41]
2 years ago
14

Christian sets aside $60 per month for daily coffee. McDonalds sells coffee for $1, and The Bean Sprout sells a cup of coffee fo

r $3.Create an equation that represents the combinations of coffee options that allow Christian to stay in his budget.Graph the equation for his budget.Provide 2 combinations that use his entire budget, 1 combination that would be under budget, and 1 combination that would be over his budget.
Mathematics
1 answer:
VladimirAG [237]2 years ago
4 0

Since Christian sets aside $60 per month for daily coffee, and McDonalds sells coffee for $ 1, and The Bean Sprout sells a cup of coffee for $3, to create an equation that represents the combinations of coffee options that allow Christian to stay in his budget and provide 2 combinations that use his entire budget, 1 combination that would be under budget, and 1 combination that would be over his budget, the following linear equation must be proposed:

 

M + BS = 60

2 combinations using the entire budget =

  • 15 McDonalds + 15 The Bean Sprout = 15 + 45 = 60
  • 30 McDonalds + 10 The Bean Sprout = 30 + 30 = 60

1 combination under budget =

  • 15 McDonalds + 10 The Bean Sprout = 15 + 30 = 45

1 combination over budget =

  • 30 McDonalds + 30 The Bean Sprout = 30 + 90 = 120

Learn more in brainly.com/question/14305871

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Daniela sells handmade purses for $22. She
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Answer:

6 purses

Step-by-step explanation

1. Subtract 71 from 161 as that's how much Daniela needs to make to have 161, which is 90

2. Divide 15 by 90 as 15 is the profit, so the answer would be the amount of purses she needs to sell, then you get 6

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6 times 15, 90

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A door delivery florist wishes to estimate the proportion of people in his city that will purchase his flowers. Suppose the true
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Answer:

99.74% probability that the sample proportion will be less than 0.1

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 276, p = 0.06

So

\mu = E(X) = np = 276*0.06 = 16.56

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{276*0.06*0.94} = 3.9454

What is the probability that the sample proportion will be less than 0.1

This is the pvalue of Z when X = 0.1*276 = 27.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{27.6 - 16.56}{3.9454}

Z = 2.8

Z = 2.8 has a pvalue of 0.9974

99.74% probability that the sample proportion will be less than 0.1

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