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3 years ago

Find the area of each figure below

Mathematics

1 answer:

Ugo [173]3 years ago

7 0

Answer:

25. $27a^{3}b^{2}$

26. $3\pi x^{3}y$

Step-by-step explanation:

For 25:

$A = \frac{a+b}{2} h$ (area of a trapezoid)

$A=\frac{11a^{2}b+7a^{2}b}{2} *3ab$ (substitute terms)

$= \frac{18a^{2}b}{2}*3ab$ (collect like terms)

$= 9a^{2}b*3ab$ (reduce the fraction by crossing out 2)

$= 27a^{3}b^{2}$ (calculate)

For 26:

$A=\pi r^{2}$ (equation of area of a circle)

$A=\pi (3x^{3} y)^{2}$ (enter the radius)

$= 3\pi x^{3} y$ (communtative property to reorder the terms)

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You rent an apartment that costs $1200 per month during the first year, but the rent

dimaraw [331]

Answer:

So first we have to figure out what $1200 per month for 12 months is since it was a year. 1200x12=14,400 a year which is outrageous for an apartment just saying.

Then we find out what 12% of the 1200 is and then add it to 1200.

To find the percentage of that we need to know how many times 12 fits into 100% 12 fits into 100 a total of 8.33333333333 times.

So now we divide 1200 by 8.33333333333 to see what 12% of it is.

1200 divided by 8.33333333333 is 144. So 1200+144=1344.

Now since one of the nine years has passed already we only have 8 remaining.

Now we see what 1344 a month for 12 months is 16,128 a year.

Now we multiply 16,128 by 8 to get the outcome of 8 more years. So 16,128x8=129,024

Thats it pls mark brainliest

Step-by-step explanation:

7 0

3 years ago

The president of a small manufacturing firm is concerned about the continual increase in manufacturing costs over the past sever

mrs_skeptik [129]

Answer:

The answers to the question are

(a) The time series plot is given as attached

(b) The parameters for the line that minimizes MSE for the time series are;

y-intercept, b₀ = 19.993

Slope, b₁ = 1.77

MSE = 19.44

T $_t$ = 19.993 + 1.774·t

(d) The estimate of the cost/unit for next year is $35.96.

Step-by-step explanation:

(a) Using the provided data, the time series plot is given as attached

(b) Given hat the y-intercept, = b₀

Slope = b₁

Therefore the linear trend forecast equation is given s

T $_t$ = b₀ + b₁·t

The linear trend line slope is given as

b₁ = $\frac{\Sigma^n_{t=1}(t-\overline{\rm t)}(Y_t-\overline{\rm Y)}}{\Sigma^n_{t=1}(t-\overline{\rm t} )^2}$

b₀ = $\overline{\rm Y}$ - b₁· $\overline{\rm t}$

Where:

Y $_t$ = Time series plot value at t

n = Time period number

$\overline{\rm Y}$ = Time series data average value and

$\overline{\rm t}$ = Average time, t

Therefore, $\overline{\rm t}$ = $\frac{\Sigma^n _{t=1} t}{n} = \frac{36}{8} =4.5$

$\overline{\rm t}$ = 4.5

$\overline{\rm Y}$ = $\frac{\Sigma^n _{t=1} Y_t}{n} = \frac{223.8}{8} =27.975$

$\overline{\rm Y}$ = 27.975

Therefore the linear trend line equation T $_t$ , is

b₁ = $\frac{\Sigma^n_{t=1}(t-\overline{\rm t)}(Y_t-\overline{\rm Y)}}{\Sigma^n_{t=1}(t-\overline{\rm t} )^2}$ = $= \frac{74.5}{42}$ = 1.774

b₀ = $\overline{\rm Y}$ - b₁· $\overline{\rm t}$ = 27.975 - 1.774×4.5 = 19.993

Therefore the trend equation for the linear trend is

T $_t$ = 19.993 + 1.774·t

MSE = $\frac{1}{2} \Sigma(Y-\overline{\rm Y)^ }^2$ = $\frac{155.495}{8}$ = 19.44

Therefore the average cost increase that the firm has been realizing per year is $ 1.77

(b) From the equation of the future trend, we have when y = 9

T $_t$ is given as

T $_t$ = 19.993 + 1.774×9 = 35.96

The cost/unit for 9th year is $35.96

3 0

3 years ago

283 is the same as the quotient of 97 and u

Margaret [11]

Answer:

283=97/u U=2.917

Step-by-step explanation:

if you have choices and more information, it would be helpful when answering questions

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2 years ago

Find the quotation -10/-5= need help ASAP

natita [175]

Answer:

Step-by-step explanation:

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3 years ago

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Oksana_A [137]

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