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morpeh [17]
3 years ago
12

Find the area of each figure below

Mathematics
1 answer:
Ugo [173]3 years ago
7 0

Answer:

25. 27a^{3}b^{2}

26. 3\pi x^{3}y

Step-by-step explanation:

For 25:

A = \frac{a+b}{2} h  (area of a trapezoid)

A=\frac{11a^{2}b+7a^{2}b}{2} *3ab  (substitute terms)

= \frac{18a^{2}b}{2}*3ab  (collect like terms)

= 9a^{2}b*3ab  (reduce the fraction by crossing out 2)

= 27a^{3}b^{2}  (calculate)

For 26:

A=\pi r^{2}  (equation of area of a circle)

A=\pi (3x^{3} y)^{2}  (enter the radius)

= 3\pi x^{3} y  (communtative property to reorder the terms)

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a fair dice is rolled. work out the probability of getting a number more than 2. give your answer in its simplest form​
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Answer:

67% (rounded)

Step-by-step explanation:

Since there is 1-6,

There is 3,4,5,6 which is 4/6 chance being above 2.

2/3 = 66.6%  

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3 years ago
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gavmur [86]
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If sin ⁡x=7/25, and 0 &lt; x &lt; π/2, what is cos⁡(x−3π/2)?
Likurg_2 [28]

Answer:

Cos(x-\frac{3\pi}{2})=-\frac{7}{25}

Step-by-step explanation:

Remember that cos(x-y)=cos(x)cos(y)+sin(x)sin(y)

Then,

cos(x-\frac{3\pi}{2})=cos(x)cos(\frac{3\pi}{2})+sin(x)sin(\frac{3\pi}{2})\\

But cos(\frac{3\pi}{2})=0 and sin(x)=\frac{7}{25}

Then

cos(x-\frac{3\pi}{2})=cos(x)*0+\frac{7}{25}*sin(\frac{3\pi}{2})\\=\frac{7}{25}*(-1)=\frac{-7}{25}

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3 years ago
What conversion factor would you use to solve thikproblem?
ira [324]

Conversion factor is the term that is to be multiplied to a variable when converting between units. The conversion factor is: 2.20lbs /kg

Given that:

54kg \to x\ lbs

From standard unit of conversion:

1kg = 2.20lbs

So, we have:

54kg \to x\ lbs

1kg = 2.20lbs

Cross multiply

54kg \times 2.20lbs = xlbs \times 1kg

Divide both sides by 1kg

54kg \times 2.20lbs /kg= xlbs

Rewrite as:

x = 54kg \times 2.20lbs /kg

Hence, the conversion factor is: 2.20lbs /kg

Read more about conversion factors at:

brainly.com/question/6988886

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2 years ago
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