Let's
simplify step-by-step.
3x2(x2−4x−4)+5x3+7x2+2x+11
Distribute:
=(3x2)(x2)+(3x2)(−4x)+(3x2)(−4)+5x3+7x2+2x+11
=3x4+−12x3+−12x2+5x3+7x2+2x+11
Combine
Like Terms:
=3x4+−12x3+−12x2+5x3+7x2+2x+11
=(3x4)+(−12x3+5x3)+(−12x2+7x2)+(2x)+(11)
=3x4+−7x3+−5x2+2x+11
Answer:
=3x4−7x3−5x2+2x+11
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Answer:
Since we cannot find the square root of a negative number (at least not using the real number system), we cannot evaluate the formula any further. There will be no solutions. Use the discriminant to determine whether the quadratic equation has two, one, or no solutions. The result is a negative number. i really hope this helps u. good luck my dude
It would be 11 if I’m reading this right
Answer:
12:9
Step-by-step explanation:
Square (added characters)
