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Misha Larkins [42]

3 years ago

8

Solve for x -2.3(r - 1.2 ) = -9.66 enter you answer as decimal.

1 answer:

frozen [14]3 years ago

3 0

Answer: 5.4

Step-by-step explanation: Isolate the variable by dividing each side factors that dn't dontain the variable.

Hope this helps! :) ~Zane

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Find the value of x. A. 53–√ in B. 241−−√ in C. 55–√ in D. 9

castortr0y [4]

Answer:

<h2>x = 5√3 inches</h2>

Step-by-step explanation:

Since the triangle is a right angled triangle we can use Pythagoras theorem to find the missing side x

Using Pythagoras theorem we have

${a}^{2} = {b}^{2} + {c}^{2}$

where a is the hypotenuse

Substitute the values into the above formula

The hypotenuse is 10 inches

We have

${10}^{2} = {5}^{2} + {x}^{2}$

${x}^{2} = {10}^{2} - {5}^{2}$

${x}^{2} = 100 - 25$

${x}^{2} = 75$

We have the final answer as

<h3>x = 5√3 inches</h3>

Hope this helps you

3 0

3 years ago

Are these correct? Im having trouble

Gennadij [26K]

Answer:

yes

Step-by-step explanation:

it is correct

3 0

2 years ago

Read 2 more answers

What is the lowest common denominator of 5 and 9

lozanna [386]

It is 45 . Just simply multiply both numbers. You will get the smallest denominator

6 0

3 years ago

I need this to be 20 letters so whats 2 +2

Firdavs [7]

Answer: So what is two plus two plus two?

Well let me demonstrate. Take 2 cookies for example, your friend supplements 2 more cookies and there you have it 4 cookies. So two and two cookies are 4 cookies. Thus, 2+2=4

Step-by-step explanation: Hope I helped you out <3

-Carrie

5 0

3 years ago

What is the answer to (6+4)tothe3power-1tothe8power

Ipatiy [6.2K]

Hey there!

$\huge\boxed{(6 + 4)^3 - 1^8}$

$\huge\boxed{= 10^3 - 1^8}$

$\huge\boxed{10^3}$

$\huge\boxed{= 10\times10\times10}$

$\huge\boxed{= 100\times10 }$

$\huge\boxed{= 1,000}$

$\huge\boxed{1^{8}}$

$\huge\boxed{= 1\times1\times1 \times 1 \times 1 \times 1 \times 1 \times 1}$

$\huge\boxed{= 1 \times 1 \times 1 \times 1}$

$\huge\boxed{= 1\times1}$

$\huge\boxed{= 1}$

$\huge\boxed{1,000 - 1}$

$\huge\boxed{= 999}$

$\huge\text{Answer: \textsf{999}}$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\huge\boxed{\frak{Amphitrite1040:)}}$

8 0

2 years ago