0.88–(0.28+3.2×0.1)^2 please hurry
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Answer:
The distance from point A to the top of the building is 5 feet
The Height of the Skyscraper is 5 feet
Step-by-step explanation:
Given
Let Top point of building be point C
Also Let Base of the building be point B
Distance from point A to base B of the building AB= 5 feet
∴ It makes a Right angle triangle
Also ∠ACB = 45°
Also tan 45° = 1
Now tan ∠ACB =
∴ AB= BC =5 feet
The Height of the Skyscraper is 5 feet
Now Triangle ABC is right angle triangle with right angled at B
So by Pythagoras theorem
AC=
The distance from point A to the top of the building is 5 feet