Use photomath it’s an app and shows steps
Answer:
Thus the prime factors of the given numbers can be only 2, 3, 5, and 7. ... most 3 + 1 + 1 + 1 = 6 numbers, we are left with at least three numbers among the nine ... points, and b by blue points (for these inequalities to hold we might have to ... 8. The constant function f (x) = k, where k is a positive integer, is the only possible.
Step-by-step explanation:
Answer:
median of given data is 18
Solve the rational equation<span> by combining </span>expressions<span> and isolating the </span>variable <span>x</span><span>. I could'nt tell if you wanted me to do It in fractions or divide :/
I did it in fractons and I got
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![x = \frac{59 \sqrt{3457} \frac{59- \sqrt{x} 3457}{} }{}](https://tex.z-dn.net/?f=x%20%3D%20%20%20%20%5Cfrac%7B59%20%5Csqrt%7B3457%7D%20%5Cfrac%7B59-%20%5Csqrt%7Bx%7D%203457%7D%7B%7D%20%20%7D%7B%7D%20)
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Answer:
The probability of getting an odd number when the spinner is spun, is p(even number) = 1/2
Step-by-step explanation:
Given that the spinner has 12 equal sections labelled 1-12
Let S be the sample space
Then
S = {1,2,3,4,5,6,7,8,9,10,11,12}
![n(S) = 12](https://tex.z-dn.net/?f=n%28S%29%20%3D%2012)
Let A be the event that the outcome is an even number
Then
A = {2,4,6,8,10,12}
![n(A) = 6](https://tex.z-dn.net/?f=n%28A%29%20%3D%206)
The probability of A will be given as:
![p(A) = \frac{n(A)}{n(S)}\\\\= \frac{6}{12}\\\\= \frac{1}{2}](https://tex.z-dn.net/?f=p%28A%29%20%3D%20%5Cfrac%7Bn%28A%29%7D%7Bn%28S%29%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B6%7D%7B12%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B1%7D%7B2%7D)
Hence,
The probability of getting an odd number when the spinner is spun, is p(even number) = 1/2