7:11 is the answer ............ .
Answer:
Option d = 88
Step-by-step explanation:
Angle c = 46 degrees
46 + 46 = 92
180 - 92 = 88
Answer:
Area of polygon = 42.63 mm²
Step-by-step explanation:
Given:
To find the area of the polygon (rectangle), multiply the length with the width.
⇒ Area of polygon = LW
<u>Substitute the values into the area:</u>
⇒ Area of polygon = (8.7)(4.9) [L = 8.7 mm; W = 4.9 mm]
⇒ Area of polygon = 42.63 mm²
Answer: C. 16.4
Concept:
Here, we need to know the idea of the distance formula.
The distance formula is the formula, which is used to find the distance between any two points.
Distance = ![\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
If you are still confused, please refer to the attachment below for a clear version of the formula.
Solve:
<u>Given information</u>
(x₁, y₁) = (-3, 4)
(x₂, y₂) = (7, -9)
<u>Given expression</u>
![Distance =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=Distance%20%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
<u>Substitute values into the expression</u>
![Distance =\sqrt{(7+3)^2+(-9-4)^2}](https://tex.z-dn.net/?f=Distance%20%3D%5Csqrt%7B%287%2B3%29%5E2%2B%28-9-4%29%5E2%7D)
<u>Simplify value in the parentheses</u>
![Distance =\sqrt{(10)^2+(-13)^2}](https://tex.z-dn.net/?f=Distance%20%3D%5Csqrt%7B%2810%29%5E2%2B%28-13%29%5E2%7D)
<u>Simplify exponents</u>
![Distance =\sqrt{100+169}](https://tex.z-dn.net/?f=Distance%20%3D%5Csqrt%7B100%2B169%7D)
<u>Simplify by addition</u>
![Distance =\sqrt{269}](https://tex.z-dn.net/?f=Distance%20%3D%5Csqrt%7B269%7D)
<u>Convert square root to decimal and round the answer to the nearest tenth</u>
![\boxed{Distance=16.4}](https://tex.z-dn.net/?f=%5Cboxed%7BDistance%3D16.4%7D)
Hope this helps!! :)
Please let me know if you have any questions
Answer:
7 cans
Step-by-step explanation:
-The number of cans that can be fitted is obtained by dividing the volume of the shelf by the volume of an individual can.
-Volume of the shelf is calculated as below:
![V_{shelf}=lwh\\\\=10\times10\times4\\\\=400\ in^3](https://tex.z-dn.net/?f=V_%7Bshelf%7D%3Dlwh%5C%5C%5C%5C%3D10%5Ctimes10%5Ctimes4%5C%5C%5C%5C%3D400%5C%20in%5E3)
#We then divide by the volume of a can:
![No \ of \ cans=\frac{V_{shelf}}{V_{can}}\\\\=\frac{400}{50.24}\\\\=7.96\approx 7\ cans](https://tex.z-dn.net/?f=No%20%5C%20of%20%5C%20cans%3D%5Cfrac%7BV_%7Bshelf%7D%7D%7BV_%7Bcan%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7B400%7D%7B50.24%7D%5C%5C%5C%5C%3D7.96%5Capprox%207%5C%20cans)
We round down since the 8th can cannot properly fit.
Hence, only 7 cans will fit in the shelf