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Sladkaya [172]
2 years ago
6

How are the semicircle and the diameter of a circle related?

Mathematics
2 answers:
k0ka [10]2 years ago
3 0

Answer:

rThe degree of measure of the simicircle are the same.

Step-by-step explanation:

Im almost positive this is right..

Orlov [11]2 years ago
3 0

Answer:

B. The degree measure of the diameter and the degree measure of the semicircle are the same.

Step-by-step explanation:

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What is the equation of the line ? Please help !!!! First and correct answer will get brainestttt
sergeinik [125]

Answer:

Step-by-step explanation:

Find the slope by doing rise/run

-2/3

Find the y intercept: (0, -2)

The equation will be y = -\frac{2}{3}x - 2

6 0
3 years ago
The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct
lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

y=\dfrac{x}{1+x}

Point P\left(1,\dfrac{1}{2}\right) lies on the curve.

Point Q\left(x,\dfrac{x}{1+x}\right) is an arbitrary point on the curve.

The slope of the secant line PQ is

\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]

1. If x=0.5, then the slope is

\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333

2. If x=0.9, then the slope is

\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632

3. If x=0.99, then the slope is

\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513

4. If x=0.999, then the slope is

\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501

5. If x=1.5, then the slope is

\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2

6. If x=1.1, then the slope is

\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381

7. If x=1.01, then the slope is

\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488

8. If x=1.001, then the slope is

\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499

7 0
3 years ago
18. Two planes left an airport at the same time. One flew north at a set speed and the other
Andre45 [30]

Answer: plane A = 333.33mph

Plane B = 500mph

Step-by-step explanation:

Given data:

Distance between the two planes = 2400miles.

Plane A flew North

Plane B flew south

Solution:

Let v represent plane A.

Let 2v represent plane B.

Distance between the two plane

v + 1.5* v = 3*v

7.5v = 2500miles

v = 333.33mph

Plane B has one and half times the speed of plane A

= 1.5 * 333.33

= 500mph

4 0
3 years ago
7.05, 5.07,7.5,0.57 least to greatest
Rudiy27

0.57 , 5.07 , 7.05 , 7.5

7 0
3 years ago
Read 2 more answers
PLEASE HELP I WILL MARK YOU BRAINLIEST
kakasveta [241]

Answer:

84 square centimetres

Step-by-step explanation:

Split the figure into multiple smaller figures. Then multiply the side lengths and add them all together.

6 0
3 years ago
Read 2 more answers
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