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Sladkaya [172]
2 years ago
6

How are the semicircle and the diameter of a circle related?

Mathematics
2 answers:
k0ka [10]2 years ago
3 0

Answer:

rThe degree of measure of the simicircle are the same.

Step-by-step explanation:

Im almost positive this is right..

Orlov [11]2 years ago
3 0

Answer:

B. The degree measure of the diameter and the degree measure of the semicircle are the same.

Step-by-step explanation:

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Please help. If f(x)= 2^x-1+3 and g(x)=5x-9 what is (f-g)(x)??
Readme [11.4K]

( f + g ) (x) = –2x + 6

( f – g ) (x) = 8x – 2

( f  × g ) (x) = –15x2 + 2x + 8

<span>\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}<span><span>(<span><span>​g</span>​<span>​f</span><span>​​</span></span>)</span>(x)=<span><span>​<span>4−5x</span></span>​<span>​<span>3x+2</span></span><span>​​</span></span></span></span>

4 0
3 years ago
Read 2 more answers
Kaya had a string 6 1/8 inches long. She cut off a piece 2 3/4 inches long. How long is the remaining piece of string? Show your
Katen [24]

Answer: 3 3/8

Step-by-step explanation:

We know that for example 2/4=4/8 so it is multiplied by 2. In this problem the fractions are 2 2/4 and 6 1/8. We are subtracting so you would first multiply the fraction that’s going to subtracted from the other fraction 2 3/4= 2 6/8. Now that we have our fractions we can subtract 6 1/8-2 6/8 this would leave us with 3.375 which is equal to 3 3/8.

4 0
2 years ago
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What is the area of this composite figure, in square centimeters?<br> 176<br> 209<br> 242<br> 264
e-lub [12.9K]

Answer:

209

Step-by-step explanation:

We can divide the figure into 2 parts to make this easier.

11x16=176 so the square is 176 square cm.

(11x6)/2 = 66/2 = 33 so the triangle is 33 square cm.

176+33 = 209 sq cm.

3 0
3 years ago
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What is 20% off 123.74?
Marina CMI [18]
20% of 123.74 can be represented like so:

123.74 * (20/100)

Which is

123.74 * (1/5)

Which is

123.74 ÷ 5

Which equals your answer,

24.748
8 0
3 years ago
Let f = (ax + by + 4z) i + (x + cz) j + (9y + mx) k where a, b,c, and m are constants.
Tom [10]
Let \mathcal R be an arbitrary closed region with boundary the surface \mathcal S. By the divergence theorem,

\displaysytle\iint_{\mathcal S}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV

We have

\nabla\cdot\mathbf f(x,y,z)=\dfrac{\partial(ax+by+4z)}{\partial x}+\dfrac{\partial(x+cz)}{\partial y}+\dfrac{\partial(9y+mx)}{\partial z}=a

so that the flux satisfies

\displaystyle a\iiint_{\mathcal R}\mathrm dV=0

We're assuming \mathcal R is a closed region, and the integral above is its volume, which must be positive. This means we must have a=0.
7 0
3 years ago
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