<u>Answer:</u>
![\boxed{\textsf{ Hence the solution set is$ \bf{\bigg( \dfrac{33}{4},\infty \bigg) }$}}.](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctextsf%7B%20Hence%20the%20solution%20set%20is%24%20%5Cbf%7B%5Cbigg%28%20%5Cdfrac%7B33%7D%7B4%7D%2C%5Cinfty%20%5Cbigg%29%20%7D%24%7D%7D.)
<u>Step-by-step explanation:</u>
A inequality is given to us and we need to find the solution set. So the given inequality to us is ,
<h3>
<u>★</u><u> </u><u>Hence </u><u>the </u><u>solution</u><u> </u><u>set </u><u>is </u><u>x </u><u>€</u><u> </u><u>(</u><u> </u><u>3</u><u>3</u><u>/</u><u>4</u><u> </u><u>,</u><u> </u><u>∞</u><u> </u><u>)</u><u>.</u></h3>
Answer:
Step-by-step explanation:
Note that the two equations are equivalent.
2y = 14-2x can be rearranged to y = -x+7, which is the same as the second equation. What you're looking is one line on top of the other.
Every shared point is a solution. Since there are infinitely many points on a line, and these lines share every point, there are infinitely many solutions.
The answer is three hundred
He can choose 10 tulips and 30 daffodils.<span>
</span>
The group paid $ 5250 at first city and $ 6250 at second city
<u>Solution:</u>
Let x = the charge in 1st city before taxes
Let y = the charge in 2nd city before taxes
The hotel charge before tax in the second city was $1000 higher than in the first
Then the charge at the second hotel before tax will be x + 1000
y = x + 1000 ----- eqn 1
The tax in the first city was 8.5% and the tax in the second city was 5.5%
The total hotel tax paid for the two cities was $790
<em><u>Therefore, a equation is framed as:</u></em>
8.5 % of x + 5.5 % of y = 790
![\frac{8.5}{100} \times x + \frac{5.5}{100} \times y = 790](https://tex.z-dn.net/?f=%5Cfrac%7B8.5%7D%7B100%7D%20%5Ctimes%20x%20%2B%20%5Cfrac%7B5.5%7D%7B100%7D%20%5Ctimes%20y%20%3D%20790)
0.085x + 0.055y = 790 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 1 in eqn 2</u></em>
0.085x + 0.055(x + 1000) = 790
0.085x + 0.055x + 55 = 790
0.14x = 790 - 55
0.14x = 735
<h3>x = 5250</h3>
<em><u>Substitute x = 5250 in eqn 1</u></em>
y = 5250 + 1000
<h3>y = 6250</h3>
Thus the group paid $ 5250 at first city and $ 6250 at second city