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3 years ago

6

The number of measles cases decreased by 7% to 606 cases this year. What was the number of cases prior to the increase? Express

your answer rounded correctly to the nearest whole number.

1 answer:

guapka [62]3 years ago

3 0

Answer:

652 cases

Step-by-step explanation:

The formula for percentage increase is 100 times the final-initial/final value. If we plug the numbers in and calculate, we get 652 cases. Have a great day!

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Please help me<br> Show your work

GrogVix [38]

<u>ANSWER TO PART A</u>

The given triangle has vertices $J(-4,1), K(-4,-2),L(-3,-1)$

The mapping for rotation through $90\degree$ counterclockwise has the mapping

$(x,y)\rightarrow (-y,x)$

Therefore

$J(-4,1)\rightarrow J'(-1,-4)$

$K(-4,-2)\rightarrow K'(2,-4)$

$L(-3,-1)\rightarrow L'(1,-3)$

We plot all this point and connect them with straight lines.

ANSWER TO PART B

For a reflection across the y-axis we negate the x coordinates.

The mapping is

$(x,y)\rightarrow (-x,y)$

Therefore

$J(-4,1)\rightarrow J''(4,1)$

$K(-4,-2)\rightarrow K''(4,-2)$

$L(-3,-1)\rightarrow L''(3,-1)$

We plot all this point and connect them with straight lines.

See graph in attachment

7 0

3 years ago

Help with this question Asap!! I need all the help I can get!

tankabanditka [31]

Answer:

$\large{YES}\ \dfrac{BC}{YZ}=\dfrac{AC}{XY}=\dfrac{AB}{XZ}=\dfrac{2}{1}\\\\\text{and}\ \angle B\cong\angle Z,\ \angle C\cong\angle Y,\ \angle A\cong\angle X$

Step-by-step explanation:

$BC\to ZY\\AB\to XZ\\AC\to XY\\\angle A\to\angle X\\\angle B\to\angle Z\\\angle C\to\angle Y$

$\text{We have:}\\\\\triangle ABC:\ AB=20,\ BC=12,\ AC=18\\\triangle XZY:\ XZ=10,\ YZ=6,\ XY=9\\\\\text{check the ratio:}\\\\\dfrac{AB}{XZ}=\dfrac{20}{10}=2\\\\\dfrac{BC}{YZ}=\dfrac{12}{6}=2\\\\\dfrac{AC}{XY}=\dfrac{18}{9}=2\\\\\text{CORRECT :)}\\\\\angle B\cong\angle Z,\ \angle C\cong\angle Y\\\\\text{We know that: The sum of the acute angles in a right triangle is}\ 90^o.\\\\m\angle B+m\angle A=90^o\ \text{and}\ m\angle Z+m\angle X=90^o$

$\text{We know}\ m\angle B=m\angle Z\to \ m\angle A=m\angle X.\\\text{therefore}\ \angle A\cong\angle X$

5 0

3 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

7 0

3 years ago

Draw a rhombus of side 3 cm long and a square of side 3 cm long

pochemuha

Answer: i will tell you some other day

Step-by-step explanation:

6 0

2 years ago

Solve the proportion 5/6 = c/9

AnnZ [28]

5/6= c/9

Cross mutiple. 5* 9= 45 . c*6

45= 6c

divide by 6 for 45 and 6c

45/6= 6c/6

45/6= c

Reduce 45/6. Divide by 3

45/3, 6/3

15/2= c

Answer: c= 15/2 or in decimal form , c= 7.5

3 0

3 years ago

Read 2 more answers