Answer:
7) 
9) 
11) 
Step-by-step explanation:
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Use Logarithm of a Quotient which states

And also use Logarithm of a Power which states

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So using these two properties,
7. 
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For #9, use the same logarithm propertied

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#11 is also the same concept

It is not - 5 log5(y) since only x is to the power of 5 not y
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Hope this is what you were looking for and helps you! Have a nice day/night :)