All categories

3 years ago

Will mark brainliest ⭐️⭐️⭐️⭐️⭐️

Mathematics

2 answers:

Kobotan [32]3 years ago

8 0

Answer:

answer is d

Step-by-step explanation:

dsp733 years ago

4 0

is a hope this helped

You might be interested in

How do i figure it out

olchik [2.2K]

X + x + 1 + x + 2 = 12
x + x + x + 3 = 12
subtract 3 for each side
x + x + x = 9
3x = 9
divide 3 from each side
x = 3

Small side 3 feet
Middle side 4 feet
Long side 5 feet

6 0

3 years ago

(X^2+y^2+x)dx+xydy=0 Solve for general solution

aksik [14]

Check if the equation is exact, which happens for ODEs of the form

$M(x,y)\,\mathrm dx+N(x,y)\,\mathrm dy=0$

if $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ .

We have

$M(x,y)=x^2+y^2+x\implies\dfrac{\partial M}{\partial y}=2y$

$N(x,y)=xy\implies\dfrac{\partial N}{\partial x}=y$

so the ODE is not quite exact, but we can find an integrating factor $\mu(x,y)$ so that

$\mu(x,y)M(x,y)\,\mathrm dx+\mu(x,y)N(x,y)\,\mathrm dy=0$

is exact, which would require

$\dfrac{\partial(\mu M)}{\partial y}=\dfrac{\partial(\mu N)}{\partial x}\implies \dfrac{\partial\mu}{\partial y}M+\mu\dfrac{\partial M}{\partial y}=\dfrac{\partial\mu}{\partial x}N+\mu\dfrac{\partial N}{\partial x}$

$\implies\mu\left(\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}\right)=M\dfrac{\partial\mu}{\partial y}-N\dfrac{\partial\mu}{\partial x}$

Notice that

$\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}=y-2y=-y$

is independent of x, and dividing this by $N(x,y)=xy$ gives an expression independent of y. If we assume $\mu=\mu(x)$ is a function of x alone, then $\frac{\partial\mu}{\partial y}=0$ , and the partial differential equation above gives

$-\mu y=-xy\dfrac{\mathrm d\mu}{\mathrm dx}$

which is separable and we can solve for $\mu$ easily.

$-\mu=-x\dfrac{\mathrm d\mu}{\mathrm dx}$

$\dfrac{\mathrm d\mu}\mu=\dfrac{\mathrm dx}x$

$\ln|\mu|=\ln|x|$

$\implies \mu=x$

So, multiply the original ODE by x on both sides:

$(x^3+xy^2+x^2)\,\mathrm dx+x^2y\,\mathrm dy=0$

Now

$\dfrac{\partial(x^3+xy^2+x^2)}{\partial y}=2xy$

$\dfrac{\partial(x^2y)}{\partial x}=2xy$

so the modified ODE is exact.

Now we look for a solution of the form $F(x,y)=C$ , with differential

$\mathrm dF=\dfrac{\partial F}{\partial x}\,\mathrm dx+\dfrac{\partial F}{\partial y}\,\mathrm dy=0$

The solution F satisfies

$\dfrac{\partial F}{\partial x}=x^3+xy^2+x^2$

$\dfrac{\partial F}{\partial y}=x^2y$

Integrating both sides of the first equation with respect to x gives

$F(x,y)=\dfrac{x^4}4+\dfrac{x^2y^2}2+\dfrac{x^3}3+f(y)$

Differentiating both sides with respect to y gives

$\dfrac{\partial F}{\partial y}=x^2y+\dfrac{\mathrm df}{\mathrm dy}=x^2y$

$\implies\dfrac{\mathrm df}{\mathrm dy}=0\implies f(y)=C$

So the solution to the ODE is

$F(x,y)=C\iff \dfrac{x^4}4+\dfrac{x^2y^2}2+\dfrac{x^3}3+C=C$

$\implies\boxed{\dfrac{x^4}4+\dfrac{x^2y^2}2+\dfrac{x^3}3=C}$

5 0

3 years ago

Please solve for X and Y. -7x-9y= -18 -2x-7y= 17

Musya8 [376]

Answer:

Step-by-step explanation:

8 0

3 years ago

Two competing gyms each offer childcare while parents work out

KIM [24]

I'm sorry, what is the question here?

8 0

3 years ago

Find the value of each variable. Line / is a tangent

Mashcka [7]

Answer:

a° = 118° , b° = 49° , c° = 144° , d° = 98°

Step-by-step explanation:

* Lets study the figure and take the information to solve the question

- There is a circle

- There is an inscribed triangle in the circle

- Each vertex of the triangle is an inscribed angle in the circle

- Each vertex subtended by an arc

- The measure of any inscribed angle is half the measure of its

subtended arc

* Now lets solve the question

- The sum of the measures of the interior angles of a triangle is 180°

∵ The triangle has angle of measure 59° and another angle of

measure 72°

∴ The measure of the third angle = 180° - (59° + 72°) = 49°

∵ b° is the measure of the third angle in the triangle

∴ b° = 49°

- The arc of measure a° is intercept the angle of measure 59°

∵ The measure of the angle is half the measure of the arc

∴ 1/2 a° = 59° ⇒ multiply both sides by 2

∴ a° = 118°

- The arc of measure c° is intercept the angle of measure 72°

∵ The measure of the angle is half the measure of the arc

∴ 1/2 c° = 72° ⇒ multiply both sides by 2

∴ c° = 144°

- The arc of measure d° is intercept the angle of measure 49°

∵ The measure of the angle is half the measure of the arc

∴ 1/2 d° = 49° ⇒ multiply both sides by 2

∴ d° = 98°

4 0

3 years ago