Answer:
4a-b-c
Step-by-step explanation:
we first look at the letters of each number. if there is only a letter, there is an imaginary 1 in front of it. we need to make sure that we add the numbers that have the exact same letters because they are known as like terms. we cannot add 6a and 4b because the letters are different and they are known as unlike terms. When we add numbers with the same letter ONLY the number changes
Correct is AB = DC
AB and DC are opposite sides of a rectangle which are equal.
Answer:
A) Ms. Swift can conclude that hey are similar, because line E,C,A is collinear, and they both are right triangles.
B) 158.3ft
Step-by-step explanation:
A) Having a collinear line makes the triangles similar, and because of their collinear line they are both right triangles.
B) The question tells you DE is 103 ft. You take 76ft and Square it giving you 5776ft You then take 103 and square it giving you 10609ft adding them together gives you 16385ft you take the square root of it and it gives you the hypotenuse of triangle CDE. To get the hypotenuse of triangle ABC you take The expression (AB/DE)=(BC/CD)=(AC/EC) step one (AB/DE)=(94ft/76ft)=AC/DE) step two (103ft/127ft)=(94ft/76ft)=(AC/DE) third step (103ft/127ft)=(94ft/76ft)=(128ft/158.3)
I truly hope this helps! :)
Any number inside the modulus sign becomes positive. This means
and so we have,

Solving these gives us


However if we check the second solution in the original equation we obtain
. This is false and so
can't be a solution.
Therefore the only solution is
.
(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)