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anzhelika [568]
3 years ago
15

Find the value of x in the triangle shown below choose 1 answer

Mathematics
2 answers:
pashok25 [27]3 years ago
5 0

Answer:

x=10

Step-by-step explanation:

X^2=6^+8^

x^2=36=64

x^2=100, square root of 100 =10

x=10

miss Akunina [59]3 years ago
5 0
Its 10 ! hope this helps !
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(266+x)/4 = 90
(Multiply by 4 on each side to get rid of it)

266+x=360
(subtract 266 from each side)

x = 94


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7 0
4 years ago
10(2^×) + 7(3^×) = 6^× + 70​
Mkey [24]

Answer:

x = 2.81 and 2.096

Step-by-step explanation:

Given the expression

10(2^x) + 7(3^x) = 6^x + 70​

This can also be expressed as;

10(2^x) + 7(3^x) = (2*3)^x + 70

10(2^x) + 7(3^x) = 2^x*3^x + 70

Let a  = 2^x and b = 3^x

10a + 7b = ab + 70

10a + 7b - ab = 70

10a-ab + 7b - 70 = 0

a(10-b)+7(b-10) = 0

a(10-b)-7(10-b) = 0

a-7 = 0 and 10-b = 0

a = 7 and b = 10

Since a = 2^x

7 = 2^x

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log7 = xlog2

x = log7/log2

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x = log 10/log 3

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x = 2.096

Hence the values of x that satisfies the equation are 2.81 and 2.096

8 0
3 years ago
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