Well you jus t split a box into 4parts and each box is worth 5
Answer:
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
Step-by-step explanation:
Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.
In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.
Yea me ether did you ever find the answer
1) (m³n⁵)(mn⁴)
-----------------
m⁻³n²
Simplify.
m⁴n⁹
-------
m⁻³n²
When the bottom power is a negative, you add it to the power on top, & when the power is a positive, you subtract it.
m⁴ + m³ = m⁷
n⁹ - n² = n⁷
So, our answer for #1 is m⁷n⁷
2) 6a²b³
---------
4a
Please read rules in #1.
6 / 4 = 3/2 & a² - a = a
So, our answer is 3a
-----
2
3) 5⁶a⁶b³
---------
5²ab³
5⁶ - 5² = 5⁴ AND a⁶ - a = a⁵ AND b³-b³ = 0
So, our answer is 5⁴a⁵
Simplify 5⁴
5 × 5 × 5 × 5 = 625
So, our final answer is :
625a⁵
~Hope I helped!~
Answer:
There is no sufficient evidence
Step-by-step explanation:
See attached files
