The median weight for shelter A is greater than that for shelter B.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
Hope this helps :-)
3 times i’m pretty sure it’s three times more
Answer:

Step-by-step explanation:
Answer:
b) y = 2/3x
Step-by-step explanation:
Slope (m) formula: 
I will be using (3,2) and (-3,-2) to find the slope:


(3,2)


Hope this helps!
Horizontal, by the way don listen to that just trying to get points