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AlekseyPX
3 years ago
12

Which equation, in slope-intercept form, passes through (–2, 4) and has a

Mathematics
1 answer:
kipiarov [429]3 years ago
8 0

Answer:

y=3x+10

Step-by-step explanation:

First, put the equation into point-slope form.

y-y1=m(x-x1)

y-4=3(x+2)

Next, distribute 3 to (x+2) and simplify.

y-4=3x+6

y=3x+10

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Angelina_Jolie [31]

Answer:

15.13cm

Step-by-step explanation:

From that above question:

We are told that:

Lateral surface area of a right circular cone : πr√r² + h²

We are give the following parameters:

Lateral surface area = 236.64cm²

Radius = 4.75cm

We are to find the height

Making h the subject of the formula

h = √[(A/r)² - πr²]/π

h = √[(236.64/4.75)²- π ×4.75²]/π

h = 15.12975 cm

Approximately to the nearest hundredth = 15.13cm

7 0
3 years ago
Write a inequality for the sentence then solve the inequality
Digiron [165]
It would be letter. b....
6 0
3 years ago
Read 2 more answers
Please solve this problem and show your work !! Please answer this !!
anastassius [24]

Answer:

-18k^2+72kx+54x^2

Step-by-step explanation:

Sorry i don't have the step-by-step but that's the answer

4 0
4 years ago
Determine which of the indicated column vectors are eigenvectors of the given matrix
gladu [14]
]Eigenvectors are found by the equation (A-\lambda I) \vec{v} = 0$ implying that \det(A-\lambda I) = 0. We then can write:

A-\lambda I = \left [ \begin{array}{cc} 4-\lambda & 2 \\ 5 & 1-\lambda \end{array}\right ] 

And:

\det(A-\lambda I) = (4-\lambda)(1-\lambda) - 10 = 0 

Gives us the characteristic polynomial:

\lambda^2 - 5 \lambda -6 = 0 \implies \lambda_1 = -1, \lambda_2 = 6

So, solving for each eigenvector subspace:

\left [ \begin{array}{cc} 4 & 2 \\ 5 & 1 \end{array} \right ] \left [ \begin{array}{c} x \\ y \end{array} \right ] = \left [ \begin{array}{c} -x \\ -y \end{array} \right ]

Gives us the system of equations:

4x + 2y = -x \newline 5x + y = - y 

Producing the subspace along the line y = -\frac{5}{2} x

We can see then that 3 is the answer. 



7 0
3 years ago
The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho
lyudmila [28]

Answer:

  • <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>

Explanation:

<u>Rewrite the table and the choices for better understanding:</u>

<em>Enrollment at a Technical School </em>

Year (x)       First Year f(x)      Second Year s(x)

2009                  785                        756

2010                   740                        785

2011                    690                        710

2012                   732                         732

2013                   781                          755

Which of the following statements is true based on the data in the table?

  • The solution to f(x) = s(x) is x = 2012.
  • The solution to f(x) = s(x) is x = 732.
  • The solution to f(x) = s(x) is x = 2011.
  • The solution to f(x) = s(x) is x = 710.

<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>

Thus, the correct choice is the third one:

  • The solution to f(x) = s(x) is x = 2012.
5 0
4 years ago
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