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4 years ago

Which equation is NOT an identity?

Mathematics

1 answer:

Simora [160]4 years ago

7 0

Answer:

Step-by-step explanation:

If you add 0 to anything, you do not have anything new when you are finished. A is an identity.

When you multiply 1 times anything, you do not get anything new. B is an identity

When you switch the order of two numbers and they are not affected by signs, then you are using the commutative property of addition. Nothing changes. C is an identity.

D is the problem child. Nothing I can think of right now will not change will you add 1 to it. If you can think of something that doesn't change when you add one to it, please put it in the comments. Otherwise, D is not an identity.

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saw5 [17]

Answer:

Step-by-step explanation:

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3 years ago

Suppose that you want to mix two coffees in order to obtain 100 pounds of a blend. If x represents the number of pounds of coffe

Fantom [35]

Answer:

The required expression that represents the number of pound of coffees B is $100-x$

Step-by-step explanation:

Consider the provided information.

You want to mix two coffees in order to obtain 100 pounds of a blend.

Let x represents the number of pounds of coffee A and y represents the number of pounds of coffee B.

The obtained weight is 100 pounds.

$x+y=100$

$y=100-x$

Hence, the required expression that represents the number of pound of coffees B is $100-x$

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3 years ago

A right triangle has a leg of 17 cm and a hypotenuse of 25 cm. What is the length of the other leg? Round to the nearest tenth.

Rudik [331]

Answer:

18.3

Step-by-step explanation:

Pythagorean Theorem = a^2 + b^2 = c^2

a, b = legs

c = hypotenuse

17^2 + b^2 = 25^2

b = 18.3

3 0

2 years ago

Read 2 more answers

X^2-5x-8=0 find the roots (zeros)

melomori [17]

Answer:

$x_1=\dfrac{5-\sqrt{57}}{2}\ ,\quad x_2=\dfrac{5+\sqrt{57}}{2}$

Step-by-step explanation:

$x^2-5x-8=0\\\\a=1\,,\ b=-5\,,\ c=-8\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot1\cdot(-8)}}{2\cdot1}=\dfrac{5\pm\sqrt{25+32}}{2}=\dfrac{5\pm\sqrt{57}}{2}$