1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dovator [93]
3 years ago
10

A rectangular garden has a walkway around it. The area of the garden is 4(5.5x + 2.5). The

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0

Answer:

a = 22x + 23

Step-by-step explanation:

area walkway = area both - area garden

a = 5.5(8x + 6) - 4(5.5x + 2.5)

Distribute

a = (44x + 33) - (22x + 10)

Simplify

a = 44x + 33 - 22x - 10

Combine like terms

a = 22x + 23

You might be interested in
The circumference (C) of a swimming pool is 47 feet. Which formula can you use to find the radius (r) if you know that C = 2πr
kondor19780726 [428]
You don't have to use a formula, all you have to do is use basic algebra to modify the equation in front of you. Simply divide both sides by 2pi and you will end up with C/2pi = r. Then, just type it into your calculator and you're good to go!
7 0
3 years ago
Read 2 more answers
Which of the following theorems cannot be used to prove two lines are<br> parallel?
mariarad [96]

Answer:

Option H

Step-by-step explanation:

Option F

If two lines are cut by a transversal so that a pair of corresponding angles are congruent, then the lines are parallel.

True.

Option G

If two lines are cut by a transversal so that a pair of alternate exterior angles are congruent, then the lines are parallel.

True

Option H

If two line are cut by a transversal so that a pair of vertical angles are congruent, then the lines are parallel.

Since, vertical angles don't prove the lines cut by a transversal are parallel.

So the statement is False.

Option J

If two lines are are cut by a transversal so that a pair of same side interior angles are supplementary, then the lines are parallel.

True.

6 0
3 years ago
Let Z be a standard normal random variable and calculate the following probabilities, drawing pictures wherever appropriate. (Ro
puteri [66]

Answer:

(a) P(0 ≤ Z ≤ 2.87)=0.498

(b) P(0 ≤ Z ≤ 2)=0.477

(c) P(−2.20 ≤ Z ≤ 0)=0.486

(d) P(−2.20 ≤ Z ≤ 2.20)=0.972

(e) P(Z ≤ 1.01)=0.844

(f) P(−1.95 ≤ Z)=0.974

(g) P(−1.20 ≤ Z ≤ 2.00)=0.862

(h) P(1.01 ≤ Z ≤ 2.50)=0.150

(i) P(1.20 ≤ Z)=0.115

(j) P(|Z| ≤ 2.50)=0.988

Step-by-step explanation:

(a) P(0 ≤ Z ≤ 2.87)

In this case, this is equal to the difference between P(z<2.87) and P(z<0). The last term is substracting because is the area under the curve that is included in P(z<2.87) but does not correspond because the other condition is that z>0.

P(0 \leq z \leq 2.87)= P(z

(b) P(0 ≤ Z ≤ 2)

This is the same case as point a.

P(0 \leq z \leq 2)= P(z

(c) P(−2.20 ≤ Z ≤ 0)

This is the same case as point a.

P(-2.2 \leq z \leq 0)= P(z

(d) P(−2.20 ≤ Z ≤ 2.20)

This is the same case as point a.

P(-2.2 \leq z \leq 2.2)= P(z

(e) P(Z ≤ 1.01)

This can be calculated simply as the area under the curve for z from -infinity to z=1.01.

P(z\leq1.01)=0.844

(f) P(−1.95 ≤ Z)

This is best expressed as P(z≥-1.95), and is calculated as the area under the curve that goes from z=-1.95 to infininity.

It also can be calculated, thanks to the symmetry in z=0 of the standard normal distribution, as P(z≥-1.95)=P(z≤1.95).

P(z\geq -1.95)=0.974

(g) P(−1.20 ≤ Z ≤ 2.00)

This is the same case as point a.

P(-1.20 \leq z \leq 2.00)= P(z

(h) P(1.01 ≤ Z ≤ 2.50)

This is the same case as point a.

P(1.01 \leq z \leq 2.50)= P(z

(i) P(1.20 ≤ Z)

This is the same case as point f.

P(z\geq 1.20)=0.115

(j) P(|Z| ≤ 2.50)

In this case, the z is expressed in absolute value. If z is positive, it has to be under 2.5. If z is negative, it means it has to be over -2.5. So this probability is translated to P|Z| < 2.50)=P(-2.5<z<2.5) and then solved from there like in point a.

P(|z|

7 0
3 years ago
Read 2 more answers
Before being simplified, the instructions for computing income tax in Country R were to add 2 percent of one’s annual income to
Vedmedyk [2.9K]

Answer:

Option C)

50 + \dfrac{I}{40}          

Step-by-step explanation:

We are given the following in the question:

I is the annual income of a person in a country R

2 percent of one’s annual income =

\dfrac{2}{100}\times I = 0.02I

1 percent of one’s annual income =

\dfrac{1}{100}\times I = 0.01I

Average of  100 units of Country R’s currency and 1 percent of one’s annual income.

=\dfrac{0.01I + 100}{2}

Income tax =

2 percent of one’s annual income + Average of  100 units of Country R’s currency and 1 percent of one’s annual income.

= 0.02I + \dfrac{100+0.01I}{2}\\\\=50 + \dfrac{0.04I + 0.01I}{2}\\\\=50 + \dfrac{0.05I}{2}\\\\= 50 + \dfrac{I}{40}

Thus, income tax is given by

Option C)

50 + \dfrac{I}{40}

6 0
3 years ago
Find the domain for the rational function:
jenyasd209 [6]

Answer:

3rd Option

Step-by-step explanation:

Since the denominator cannot equal 0, x ≠ 5. Therefore, our domain stops and starts again at 5. So our answer is 3rd option.

3 0
3 years ago
Other questions:
  • Can someone help me with this question
    7·1 answer
  • Rolex borrowed $3200 from his credit union for 4 years. He was charged 9.8% simple interest. What was the total amount he owed t
    10·1 answer
  • Explain how you would order from least to greatest three numbers that include a positive number, a negative number , and a zero
    15·2 answers
  • Can someone help me solve this radical expressions? Thank you and please show steps!!
    14·1 answer
  • Helppppp i need itttttt
    6·1 answer
  • A to the 8th power ÷ by a to the 3 rd power
    11·2 answers
  • Tell whether the equation has one, zero, or infinitely many solutions.9(x − 3) + 15 = 9x − 11.
    12·2 answers
  • PLEASE ANSWER ASAp thank you
    12·2 answers
  • Another easy one, Brainliest + 35 Points. per the usual
    8·2 answers
  • How many solutions does the following equation have? 2 x-4=4-2x
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!