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NISA [10]
3 years ago
5

6. Monique is making an ottoman for her living room. She covers the top of the ottoman with fabric. How much surface would she n

eed to stain, if she stains the sides of the ottoman (excluding the bottom)?

Mathematics
1 answer:
pantera1 [17]3 years ago
7 0
I believe she would need to stain 548 inches of the surface.

Excluding the top and bottom, you are left with two panels that are 10 by 7.4, and two panels that are10 by 20, so

10•7.4= 74•2 =148
10•20= 200•2 =400
148 + 400= 548

Please correct me if I am wrong, have a good day!
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2,300+-2,500+3,300+-2,600+6,250
Lorico [155]
1 Simplify

<span><span>2300−2500+3300−2600+6250</span>
2 Simplify

<span><span>6,750

I hope this helps. 

Have a awesome day. :)

</span><span>
</span></span><span>

</span></span>
5 0
4 years ago
Read 2 more answers
Find the value of x in the Diagram Below.
zhannawk [14.2K]
Answer: x = 12

Step-By-Step: 180 - 100 = 80

Step-By-Step: 80 - 12 = 68

Step-By-Step: 68 is angle ( X + 12)

68 + 12 = 80 + 100 equals 180

6 0
3 years ago
What is the interquartile range for the data set 4,7,7,3,5,2,6,7,9 the answers are 3.5, 5.6, 7,9
polet [3.4K]
5.6 is the answer for your question
5 0
3 years ago
5/8 of an inch in percent
Dovator [93]
<h2>Greetings!</h2>

Answer:

62.5%

Step-by-step explanation:

To find the percentage, you simply need to divide the number on top by the number on bottom and multiply by 100:

5 ÷ 8 = 0.625

0.625 x 100 = 62.5

So the percentage is 62.5%!


<h2>Hope this helps!</h2>
6 0
4 years ago
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What situations would solve by graphing be your preferred choice? Give an example.
Damm [24]

Answer:

1) The solve by graphing will the preferred choice when the equation is complex to be easily solved by the other means

Example;

y = x⁵ + 4·x⁴ + 3·x³ + 2·x² + x + 3

2) Solving by substitution is suitable where we have two or more variables in two or more (equal number) of equations

2x + 6y = 16

x + y = 6

We can substitute the value of x = 6 - y, into the first equation and solve from there

3) Solving an equation be Elimination, is suitable when there are two or more equations with coefficients of the form, 2·x + 6·y = 23 and x + y = 16

Multiplying the second equation by 2 and subtracting it from the first equation as follows

2·x + 6·y - 2×(x + y) = 23 - 2 × 16

2·x - 2·x + 6·y - 2·y = 23 - 32

0 + 4·y = -9

4) An example of a linear system that can be solved by all three methods is given as follows;

2·x + 6·y = 23

x + y = 16

Step-by-step explanation:

4 0
4 years ago
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