Answer:
Step-by-step explanation:
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I need help with MY MATH jejehee
We want to see how many solutions has an equation given some restrictions on the vectors of the equation.
We have 3 vectors in R2.
v₁, v₂, and v₃.
Where we know that v₁ and v₂ are parallel. And two vectors are parallel if one is a scalar times the other.
Then we can write:
v₂ = c*v₁
Where c is a real number.
Then our system:
x*v₁ + y*v₂ = v₃
Can be rewriten to:
x*v₁ + y*c*v₁ = v₃
(x + y*c)*v₁ = v₃
Assuming x, y, and c are real numbers, this only has a solution if v₁ is also parallel to v₃, because as you can see, the equation says that v₃ is a scallar times v₁.
Geometrically, this means that if we sum two parallel vectors, we will get a vector that is parallel to the two that we added.
If you want to learn more, you can read:
brainly.com/question/13322477
Answer:
cost of one cupcake = $2.75
cost of one brownie = $1.25
Step-by-step explanation:
Let c = number of cupcakes
Let b = number of brownies
Equation 1: 5c + 2b = 16.25
Equation 2: 7c + 6b = 26.75
Multiply equation 1 by 3:
⇒ 15c + 6b = 48.75
Now subtract equation 2 from this equation to eliminate 6b:
⇒ 8c = 22
Divide both sides by 8:
⇒ c = 2.75
Substitute c = 2.75 into one of the original equations and solve for b:
⇒ 5(2.75) + 2b = 16.25
⇒ 13.75 + 2b = 16.25
⇒ 2b = 2.5
⇒ b = 1.25
Therefore, cost of one cupcake = $2.75 and cost of one brownie = $1.25
