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faust18 [17]
3 years ago
7

A translation is applied to the rectangle formed by the points A(−2, 6) , B(2, 6) , C(2, 4) , and D(−2, 4) . The image is the re

ctangle that has vertices ​ A′(1, 6) ​, ​ B′(5, 6) ​, C′(5, 4) and D′(1, 4) .
Select the phrase from the drop-down menu to correctly describe the translation.

The rectangle was translated ... 3 units up
3 units to the right
3 units to the left
3 units down
Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
4 0
So basically from (-2,6) to (1,6)
The up and down translations applies to the y values 
So from 6 to 6 nothing happened! so wasn't translated neither up nor down 

And left and right applies to x values. 
from -2 to 1 
3 units positive that means 3 units right..
Hope it helps 
Gnesinka [82]3 years ago
4 0

Answer:

3 units to the right

Step-by-step explanation:

I took the test

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(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

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Step-by-step explanation:

We know the following info:

\bar X_1 = 21.9 sample mean for group 1

\bar X_2 = 19.8 sample mean for group 2

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n_2 = 200 sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

Now we just need to find the critical value. The confidence level is 0.95 then the significance is 1-0.95 =0.05 and \alpha/2 =0.025. The degrees of freedom are given by:

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The critical value for this case would be :t_{\alpha/2}=1.966  

And replacing into the confidence interval formula we got:

(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

And we are 95% confident that the true difference means are between 1.422 \leq \mu_1 -\mu_2 \leq 2.778

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