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3 years ago

Could someone help me with this? it'd be very appreciated!

Mathematics

1 answer:

Serga [27]3 years ago

8 0

Answer:

47,759

Step-by-step explanation:

77 + 216 x 326 then divide by 2

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Is 1 1/2 greater than less than or equal to 16 in

BigorU [14]

Answer:

Less than

Step-by-step explanation:

3 0

3 years ago

Which of these side lengths makes the triangle obtuse? 15, 36,

gogolik [260]

Answer:

I believe the answer is 36.

8 0

3 years ago

Deltamath Please help me I need help!!!! ⚠️Due today!!⚠️.

Vedmedyk [2.9K]

Answer:

(7,4)

Step-by-step explanation:

4 0

2 years ago

the midpoint of a horizontal line segment is at x=1 if the length of the line segment is 10.5. what absolute value equation coul

egoroff_w [7]

Answer: -4.25 ≤ x ≤ 6.25

Step-by-step explanation:

The midpoint of a segment is located at the same distance of each of the endpoints of the segment.

The midpoint is at x = 1.

The length of the segment is 10.5, if we divide it by two we have:

10.5/2 = 5.25

Now, if we want the endpoints to be at the same distance of the midpoint, then the endpoints will be:

Xmax = midpoint + 5.25

Xmin = midpoint - 5.25

Then the extremes are:

Xmax = 1 + 5.25 = 6.25

Xmin = 1 - 5.25 = -4.25

Then this segment can be written as:

Xmin ≤ x ≤ Xmax

-4.25 ≤ x ≤ 6.25

8 0

3 years ago

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

3 years ago