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IrinaVladis [17]
3 years ago
5

X Find the value of x. Show 3 10 your work.

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0

Step-by-step explanation:

<em>Hello</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em><em>!</em>

<em>Let</em><em> </em><em>ABC</em><em> </em><em>be</em><em> </em><em>a Right angled triangle</em><em>, </em>

<em>where</em><em>,</em><em> </em><em>AB</em><em> </em><em>=</em><em> </em><em>3</em>

<em>BC</em><em>=</em><em> </em><em>1</em><em>0</em>

<em>and</em><em> </em><em>AC</em><em>=</em><em> </em><em>x</em>

<em>now</em><em>,</em>

<em>As</em><em> </em><em>the</em><em> </em><em>triangle</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>Right angled triangle</em><em>, </em><em>taking</em><em> </em><em>angle C</em><em> </em><em>as</em><em>refrence</em><em> </em><em>angle</em><em>.</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em> </em><em>h</em><em>=</em><em> </em><em>AC</em><em> </em><em>=</em><em> </em><em>x</em>

<em>p</em><em>=</em><em> </em><em>AB</em><em> </em><em>=</em><em> </em><em>3</em>

<em>b</em><em>=</em><em> </em><em>BC</em><em>=</em><em> </em><em>1</em><em>0</em>

<em>now</em><em>,</em><em> </em><em>by</em><em> </em><em>Pythagoras</em><em> </em><em>relation we get</em><em>, </em>

<em>h =    \sqrt{ {p}^{2} +  {b}^{2}  }</em>

<em>or ,\: h =  \sqrt{ {3}^{2}  +  {10}^{2} }</em>

<em>by</em><em> </em><em>simplifying it we get</em><em>, </em>

<em>h</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>.</em><em>4</em><em>4</em><em>0</em><em>3</em><em>0</em>

<em>Therefore</em><em>, </em><em> </em><em>the</em><em> </em><em>answer is</em><em> </em><em>x</em><em>=</em><em> </em><em>1</em><em>0</em><em>.</em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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