8z-8=6z+8
8x-6z=8+8
2z=16
Z=8
The correct question is
<span>
Penelope determined the solutions of the quadratic function by completing the square.f(x) = 4x² + 8x + 1
–1 = 4x² + 8x
–1 = 4(x² + 2x)
–1 + 1 = 4(x² + 2x + 1)
0 = 4(x + 2)²
0 = (x + 2)²
0 = x + 2
–2 = x
What error did Penelope make in her work?
we have that
</span>f(x) = 4x² + 8x + 1
to find the solutions of the quadratic function
let
f(x)=0
4x² + 8x + 1=0
Group terms that contain the same variable, and move the
constant to the opposite side of the equation
(4x² + 8x)=-1
Factor the
leading coefficient
4*(x² + 2x)=-1
Complete the square Remember to balance the equation
by adding the same constants to each side.
4*(x² + 2x+1)=-1+4 --------> ( added 4 to both sides)
Rewrite as perfect squares
4*(x+1)²=3
(x+1)²=3/4--------> (+/-)[x+1]=√3/2
(+)[x+1]=√3/2---> x1=(√3/2)-1----> x1=(√3-2)/2
(-)[x+1]=√3/2----> x2=(-2-√3)/2
therefore
the answer is
<span>
Penelope should have added 4 to both sides instead of adding 1.</span>
10 minutes. You see the dip or the part of the graph where it's lower than the other points? Look at how many minutes went past.
Answer:
The solutions are linearly independent because the Wronskian is not equal to 0 for all x.
The value of the Wronskian is 
Step-by-step explanation:
We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.
Thus replacing the functions of the exercise we get:
Working with the determinant we get
Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.
Answer:
B). SAS similarity.
Step-by-step explanation:
In Δ WVU & ΔCAB,
UV/CA = 17/34 = 1/2
&
VW/AB = 14/28 = 1/2
∵ UV/CA = VW/AB = 1/2
& ∠V = ∠A (Given)
∵ ΔWVU ≅ ΔCAB (by SAS similarity)
