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2 years ago

What is the graph of y = x2 + 6x + 13 ? What does the graph look like

Mathematics

1 answer:

ladessa [460]2 years ago

7 0

Answer:

If I entered it in correctly it would look something like this,,

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Evaquate -18÷3×8(-8)\-5×-2+(-2)

MArishka [77]

Answer:

-12/5 - 2

Step-by-step explanation:

-18÷3×8(-8)/-5×-2+(-2) =

-6×8(-8)/-5×-2+(-2) =

-48(-8)/-5×-2+(-2) =

6/-5×-2+(-2) =

-12/5 - 2

4 0

2 years ago

Read 2 more answers

Mimi feeds her dog 7.5 lbs of food in a week. She feeds her cat 3.75 lbs of food in a week. How many total lbs of food do her pe

algol [13]

Both of her pets eat 11.25lbs of food in a week

6 0

2 years ago

Read 2 more answers

Solve for the unknown. 3x^3=812^x-5 5x=25^3x+5 27^4x=9^x+1 3^x=9^x+5

sesenic [268]

Sorry it's quite complex, simplify then... had to use an nspire

1. x=1.22248
2. x=15624.8
3. x=0.057522 (shown in picture)
4. x=-0.732487

too bad i cant upload more than 1 pic

7 0

2 years ago

A proportional relationship between y and x. When x = 3, y=−4 .

Komok [63]

Answer:

4/3

Step-by-step explanation:

i took the quiz hehe

4 0

2 years ago

Y=x2-2x-5 Change to vertex form

MaRussiya [10]

The vertex form is $y=(x-1)^{2} -6$

Step-by-step explanation:

The given equation $y=x^{2} -2x-5$ is a parabola. The vertex of the parabola is of the form $y=ax^{2} +bx+c$

The parameters of the parabola are $a=1, b=-2$ and $c=-5$

The vertex of the x-coordinate is given by $x=\frac{-b}{2a}$

Thus, substituting the values of a and b in $x=\frac{-b}{2a}$ , we get,

$\begin{aligned}x &=\frac{-(-2)}{2(1)} \\&=\frac{2}{2} \\x &=1\end{aligned}$

Now, substituting $x=1$ in $y=x^{2} -2x-5$ , we get,

$\begin{aligned}y &=1^{2}-2(1)-5 \\&=1-2-5 \\y &=-6\end{aligned}$

Thus, the vertex is $(1,-6)$

The equation of parabola to be in vertex form is $y=a(x-h)^{2} +k$

where a is the coefficient of $x^{2}$ , h is vertex of the x-coordinate and k is the vertex of the y-coordinate.

Hence, $a=1, h=1$ and $k=-6$

Thus, substituting the values in the equation of the vertex form,

$y=1(x-1)^{2} -6\\y=(x-1)^{2} -6$

Hence, the vertex form is $y=(x-1)^{2} -6$

8 0

3 years ago