Answer:
x-intercept (-7,0)
y-intercept (0,2)
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
Answer:
The graph has a removable discontinuity at x=-2.5 and asymptoe at x=2, and passes through (6,-3)
Step-by-step explanation:
A rational equation is a equation where

where both are polynomials and q(x) can't equal zero.
1. Discovering asymptotes. We need a asymptote at x=2 so we need a binomial factor of

in our denomiator.
So right now we have

2. Removable discontinues. This occurs when we have have the same binomial factor in both the numerator and denomiator.
We can model -2.5 as

So we have as of right now.

Now let see if this passes throught point (6,-3).


So this doesn't pass through -3 so we need another term in the numerator that will make 6,-3 apart of this graph.
If we have a variable r, in the numerator that will make this applicable, we would get

Plug in 6 for the x values.



So our rational equation will be

or

We can prove this by graphing
Since the cross section is uniform, the depth of the water is irrelevant. The rate of change of height is the rate of change of volume divided by the area.
dh/dt = (dV/dt)/(π·r²)
= (9 ft³/min)/(π·(3 ft)²)
= 1/π ft/min ≈ 0.3813 ft/min
Answer:
24
/5
Step-by-step explanation:
The way I think about areas of sectors is a fraction of the pie. You know what percentage of the "pie" (in this case, circle) you want, because they give you the angle of the sector and you know a circle always has 360°. So technically, you're trying to find 48/360 th of the entire area (36
). If you're using a calculator, it doesn't matter if you simplify the fraction, but if you're doing it by hand simplifying makes everything a lot easier.
The equation will be:
Area = 24/180 × 36
= 2/15 × 36
= 72
/15
= 24
/5
I hope this helped! Also, in Khan Academy, when you get an answer wrong/right, you can view their explanation by clicking "hint" or sometimes "see how we did it" shows up.