<h2>Hello!</h2>
The answer is:
C. Cosine is negative in Quadrant III
<h2>
Why?</h2>
Let's discard each given option in order to find the correct:
A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).
B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.
C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.
D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)
Have a nice day!
Hello,
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Thanks for the incorrect formula!
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I have tested (fog)(x) ,(f*g)(x) and finally (f+g)(x)
f(x)=6x++++++++++++++++++++++++3
g(x)=x-7
(f+g)(x)=6x+3+x-7=7x-4
(f+g)(3)=7*3-4=17
Answer B
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1) Factor out the coefficient 2: 2x^2+12x=4 => 2(x^2 + 6x) = 4
2) Complete the square of x^2 + 6x: x^2 + 6x + 9 - 9. Then:
2(x^2 + 6x + 9 - 9) = 4
3) Rewrite the square as the square of a binomial:
2( [x+3]^2 - 9) = 4, or
2([x+3]^2) = 22, or
2( [x+3]^2 ) - 22 = 0
The value of q is -22.
Its 872 when the integer goes down
Answer: 9
Step-by-step explanation:
Use Pythagorean's Theorem for a right triangle.
