Let the other 2 unknown sides be y n z
look at the two smaller triangles inside
y^2 = 12^2 + x^2 and
z^2 = 21^2 + x^2
from the biggest triangle
(12+21)^2 = y^2 + z^2
substituting
(12+21)^2 = (12^2 + x^2) + (21^2 + x^2)
33^2 = 12^2 + 21^2 + 2x^2
2x^2 = (33^2 - 12^2 - 21^2)/2 = 504
x^2 = 252
x = 15.9
ans is B
3/5 of the group = 24
1/5 of the group = 8
The group = 5 x 8 = 40 .
Would it be 0,-4 and 0,-2
Answer:
7/13
Step-by-step explanation:
i just took the quiz
Ok, so
a(b-c)=ab-ac
9 is close to 10 so
828(9)=
828(10-1)=
828(10)-828(1)=
8280-828=
7000+1280-828=
7000+452=
7452
