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Elena-2011 [213]

2 years ago

7

What is the slope of the line joining (8, 8) and (12, 6)? answer choices attached

2 answers:

Margaret [11]2 years ago

3 0

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 8}}\quad ,&{{ 8}})\quad 
% (c,d)
&({{ 12}}\quad ,&{{ 6}})
\end{array}
\\\quad \\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{6-8}{12-8}$

iragen [17]2 years ago

3 0

Slope = y2-y1/x2-x1
m= 6-8/12-8
slope (m) = -1/2

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dybincka [34]

Answer:

Absolute minimum = 1.414

Absolute maximum = 2.828

Step-by-step explanation:

$g(x,y)=\sqrt {x^2+y^2} \ constraints: 1\leq x\leq 2 ,\ 1\leq y\leq2$

For absolute minimum we take the minimum values of $x$ and $y$ .

$x_{minimum} =1\\y_{minimum}=1\\$

Plugging in the minimum values in the function.

$g(1,1)=\sqrt {1^2+1^2}\\g(1,1) = \sqrt{1+1}\\g(1,1)=\sqrt {2}\\g(1,1)=\pm 1.414\\$

Absolute minimum value will be always positive.

∴ Absolute minimum = 1.414

For absolute maximum we take the maximum values of $x$ and $y$ .

$x_{maximum} =2\\y_{maximum}=2\\$

Plugging in the maximum values in the function.

$g(2,2)=\sqrt {2^2+2^2}\\g(2,2) = \sqrt{4+4}\\g(2,2)=\sqrt {8}\\g(2,2)=\pm 2.828\\$

Absolute maximum value will be always positive.

∴ Absolute maximum = 2.828

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Salsk061 [2.6K]

x-32.2= 18.5

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I hope that's help !

Check your answer

replace x by its number

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18.5 = 18.5

so the answer is good .

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