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2 years ago

I need help plzzzzzzzzzzzz. I need you guys to show work too

Mathematics

1 answer:

Softa [21]2 years ago

6 0

Answer:

Step-by-step explanation:

√(x+3) –4 = 1

√(x+3) = 1 +4

√(x+3) = 5

x + 3 = 5²

x = 25 –3

x = 22

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Write a mathematical equation that fits each word problem

Travka [436]

6.75*5=33.75

39.50-33.75

5.75/0.25

Answer 23

8 0

1 year ago

Read 2 more answers

Cynthia typed 372 words in 6 minutes what's her typing rate in words per minute

VMariaS [17]

Answer:

x = 62 words

Explanation:

→ We write the data problems.

372 words .............6 minutes

→ We must find: What's Cynthia typing rate in words per minute?

372 words .............6 minutes

x words ..................1 minute

x = 372 words * 1 minute/ 6 minutes

x = 62 words

5 0

2 years ago

A submarine was situated 800 feet below sea level.

Ghella [55]

Answer:

New position = -525 ft or 525 ft below the sea level

Step-by-step explanation:

Lets h be the height of the sea.

Given:

A submarine was situated 800 feet below sea level.

It is ascends 275 feet.

We know that h = 0 on the surface of the sea.

When we go below the surface vertically inside the sea the height will become negative.

So the submarine was situated h = -800 feet below the sea level, and it is ascends 275 feet from -800 feet.

So the new height of the submarine is.

$h = -800 + 275$

$h = -525\ ft$

Therefore the new position of the submarine is 525 below the sea level.

8 0

2 years ago

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal plac

Fed [463]

Answer:

$\theta=k\pi, \hspace{3}k\in Z\\\\ or\\\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\$

Step-by-step explanation:

Factor constant terms:

$-2(-4sin(2\theta)+sin(\theta))=0$

Divide both sides by -2:

$sin(\theta)-4sin(2 \theta)=0$

Expand trigonometric functions using the fact:

$sin(2 \theta) =2 sin(\theta) cos(\theta)$

So:

$sin(\theta) -8sin(\theta)cos(\theta)=0$

Factor sin(x) and constant terms and multiply both sides by -1:

$sin(\theta) (8cos(\theta)-1)=0$

Split into two equations:

$(1)=8cos(\theta)-1=0\\\\(2)=sin(\theta)=0$

For (1)

Add 1 to both sides and divide both sides by 8:

$cos(\theta)=\frac{1}{8}$

Take the inverse cosine of both sides:

$\theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z$

For (2)

Simply take the inverse sine of both sides

$\theta = k \pi, \hspace{3}k\in Z$

Therefore, the solutions are given by:

$\theta=k\pi, \hspace{3}k\in Z\\\\ or\\ \theta =2\pi k \pm arccos(\frac{1 }{8} ), \hspace{3}k\in Z\\$

8 0

2 years ago

A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and

IRINA_888 [86]

Answer:

The approximate percentage of cars that remain in service between 73 and 84 months

P( 73 < x < 84 ) = 0.02145 = 2.1 %

Step-by-step explanation:

Explanation:-

Given mean of the Population 'μ ' = 51 months

Standard deviation of the Population 'σ' = 11 months

Let 'X' be the random variable of Normal distribution

Let 'X' = 73

$Z = \frac{x-mean}{S.D} = \frac{73-51}{11} = 2$

Let 'X' = 84

$Z = \frac{84-51}{11} = 3$

The approximate percentage of cars that remain in service between 73 and 84 months

P( 73 < x < 84 ) = P( 2 < Z < 3)

= P( Z<3) - P( Z <2)

= 0.5 + A(3) - ( 0.5 + A(2))

= A(3) - A( 2)

= 0.49865 - 0.4772 ( From Normal table)

= 0.02145

P( 73 < x < 84 ) = 0.02145

The approximate percentage of cars that remain in service between 73 and 84 months

P( 73 < x < 84 ) = 0.02145 = 2.1 %

7 0

2 years ago