Question

Factorize py+ pz + y² + yz​

Answer 1

Answer: $(p+y)(y + z)$

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Work Shown:

$py + pz + y^2 + yz \\\\(py + pz) + (y^2 + yz) \\\\p(y + z) + (y*y + yz) \\\\p(y + z) + y(y + z) \\\\(p+y)(y + z)$

I grouped the terms into pairs. Then I factored the GCF from each pair

The GCF of py+pz is p

The GCF of y^2+yz is y

On the last line, I factored out the overall GCF (y+z)

You can use the FOIL rule or the distributive property to expand out (p+y)(y+z) and you should get the original expression back again. This is a way to confirm the correct answer.

Answer 2

Answer:

you could either say p(y+z)+y(y+z)or y(p+y)+ z(p+y)

Step-by-step explanation:

I cant really explain it but I hope this helps