The regular price of a camera is $180.00. The camera is on sale for 25% off the regular price.

What is m<efh =(5×+1)°,m<hfg =62° and m <efg = (18×+11)°, find each measure.

Naddik [55]

Answer:

$m\angle efg=21\°\\\\m\angle hfg=62\°\\\\m\angle efg=83\°$

Step-by-step explanation:

Given:

$m\angle efh=5x+1\\m\angle hfg=62\\m\angle efg=18x+11$

Now, from the figure shown below,

The sum of angle efh and angle hfg is equal to the angle efg. This is true because of the angle addition postulate which states that when two angles are formed with the same vertex and different sides, then their sum is equal to the total angle made by both the sides at the vertex.

Here, point 'f' is the vertex and the sides are 'ef and 'fg'.

Therefore,

$m\angle efh+m\angle hfg=m\angle efg$

Plug in their values and solve for 'x'. This gives,

$5x+1+62=18x+11\\5x+63=18x+11\\18x-5x=63-11\\13x=52\\x=\frac{52}{13}=4$

Therefore, the angle measure of each are:

$m\angle efg=5x+1=5(4)+1=20+1=21\°\\\\m\angle hfg=62\°\\\\m\angle efg=18x+11=18(4)+11=72+11=83\°$

6 0

4 years ago

How do you create a box plot from a set of numbers

mote1985 [20]

Answer:

You add them then, you multiply them.

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Consumer complaints are frequently reported to the Better Business Bureau. Industries with the most complaints to the Better Bus

kiruha [24]

Answer:

(a)

$\begin{array}{ccc}{Industry} & {Frequency} & {\%Frequency} & {Bank} & {26} & {13\%} & {Cable} & {44} & {22\%} & {Car} & {42} & {21\%}& {Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} & {Total} & {200} & {100\%} \ \end{array}$

(b): Cell industry

(c) See Explanation

Step-by-step explanation:

Given (Missing from the question)

$Bank = 26$

$Cable = 44$

$Car = 42$

$Cell = 60$

$Collection = 28$

$Total = 200$

Solving (a) Show the frequency and percent frequency.

The percentage frequency is calculated by:

$\%Freq = \frac{Freq}{Total} * 100\%$

So. we have:

$\%Freq = \frac{26}{200} * 100\% = 13\%$ -- Bank

$\%Freq = \frac{44}{200} * 100\% = 22\%$ --- Cable

$\%Freq = \frac{42}{200} * 100\% = 21\%$ --- Car

$\%Freq = \frac{60}{200} * 100\% = 30\%$ --- Cell

$\%Freq = \frac{28}{200} * 100\% = 14\%$ --- Collection

The table becomes:

$\begin{array}{ccc}{Industry} & {Frequency} & {\%Frequency} & {Bank} & {26} & {13\%} & {Cable} & {44} & {22\%} & {Car} & {42} & {21\%}& {Cell} & {60} & {30\%} & {Collection} & {28} & {14\%} & {Total} & {200} & {100\%} \ \end{array}$

Solving (b): The industry with the highest complaints

From the above table, the highest frequency is 60 and this represents the number of complaints of Cell industry.

Hence, the cell industry has the highest number of complaints

Solving (c): Comment

The percentage frequency table shows that the industry with the highest number of complaints is the cell industry (at 30%) and the industry with the least is the banking industry (at 13%)

5 0

3 years ago

Y + 1 = - 1/2 ( x - 7 )

likoan [24]

Answer:

1/2y * 7x

Step-by-step explanation:

5 0

3 years ago

Subtract 2x − 4 from x + 8. What's your answer?

adell [148]

Answer:

X = 8

Step-by-step explanation: So First Yu Will Add 4 On Both Sides Like Dis 2x - 4 + 4 = x + 4 + 4 Den Yu Will Simplify Which Is 2x = x + 8 After Yu Gonna Subtract x from both sides 2x - x = x + 8 - x and After Yu Got Yur Anwser Which Will B X = 8 Yur Done...

HOPE DIS HELPS YU

8 0

3 years ago