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Blababa [14]
3 years ago
8

The length of a rectangle is 3 less than 5 times the width, w. Find the perimeter of the rectangle

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0

Answer:

P = 12x -6

Step-by-step explanation:

L = 5x - 3

W = x

P = 2(L + W)

P = 2(5x -3 + x)

P = 2(6x -3)

P = 12x -6

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What is the base area.
Mariulka [41]

Answer:

Area of the base is 10.5 cm².

Step-by-step explanation:

Formula for the volume of the given oblique prism = Area of the triangular base × Vertical height between two triangular bases

Vertical height = 6 cm

Volume = 63 cm³

From the formula,

63 = Area of the triangular base × 6

Area of the base = \frac{63}{6}

                            = 10.5 cm²

Therefore, area of the base is 10.5 cm².

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3 years ago
A clinical test on humans of a new drug is normally done in three phases. Phase I is conducted with a relatively small number of
navik [9.2K]

Answer:

A clinical test on humans of a new drug is normally done in three phases. Phase I is conducted with a relatively small number of healthy volunteers. For​ example, a phase I test of a specific drug involved only 7 subjects.

Step-by-step explanation:

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3 years ago
Please help with 7-9 they are related to the same circle
Andrej [43]

40º

7) In this problem, we can see that both tangent lines to that circle come from the same point O.

So, we can write out the following considering that there is one secant line DO and one tangent line to the circle AO

\begin{gathered} m\angle1=\frac{1}{2}(160-80) \\ m\angle1=\frac{1}{2}(80) \\ m\angle1=40^{\circ} \end{gathered}

3 0
1 year ago
A guitar string is plucked at a distance of 0.6 centimeters above its resting position and then released, causing vibration. The
liubo4ka [24]

Answer:

The equation that represents the motion of the string is given by:

y =Ae^{-kt}\cos(2\pi ft)     .....[1] where t represents the time in second.

Given that: A = 0.6 cm (distance above its resting position) , k = 1.8(damping constant) and frequency(f) = 105 cycles per second.

Substitute the given values in [1] we get;

y =0.6e^{-1.8t}\cos(2\pi 105t)  

or

y =0.6e^{-1.8t}\cos(210\pi t)  

(a)

The trigonometric function that models the motion of the string is given by:

y =0.6e^{-1.8t}\cos(210\pi t)

(b)

Determine the amount of time t that it takes the string to be damped so that -0.24\leq y \leq0.24

Using graphing calculator for the equation

y =0.6e^{-1.8x}\cos(210\pi x)

let x = t (time in sec)  

Graph as shown below in the attachment:

we get:

the amount of time t that it takes the string to be damped so that -0.24\leq y \leq0.24 is, 0.5 sec


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3 years ago
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Body, Captain Hook, and Girls in the hood *chefs kiss*
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