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Blababa [14]
3 years ago
8

The length of a rectangle is 3 less than 5 times the width, w. Find the perimeter of the rectangle

Mathematics
1 answer:
marysya [2.9K]3 years ago
6 0

Answer:

P = 12x -6

Step-by-step explanation:

L = 5x - 3

W = x

P = 2(L + W)

P = 2(5x -3 + x)

P = 2(6x -3)

P = 12x -6

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Step-by-step explanation:

The angle bisector divides the sides proportionally.

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3 years ago
What two numbers have a product of -30 and a sum of -1?
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Step-by-step explanation:

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3 years ago
Read 2 more answers
2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de
Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

               M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let (x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⇒ d=\sqrt{(2-5)^2+(4-3)^2}

⇒d=\sqrt{9+1}

⇒d=\sqrt{10}   ....(1)

Now, we find the length of M'K'

let (x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)

d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}

⇒ d^{'}=\sqrt{(-2+5)^2+(3-4)^2}

⇒d^{'}=\sqrt{9+1}

⇒d^{'}=\sqrt{10} .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct


3 0
3 years ago
Read 2 more answers
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