1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pantera1 [17]
4 years ago
7

Find the missing probability. P(A)=15,P(A∪B)=1225,P(A∩B)=7100 ,P(B)=?

Mathematics
1 answer:
Llana [10]4 years ago
6 0

Answer:

<h2>p(B) = 8310</h2>

Step-by-step explanation:

We will use the addition rule of probability of two events to solve the question. According to the rule given two events A and B;

p(A∪B) = p(A)+p(B) - p(A∩B) where;

A∪B is the union of the two sets A and B

A∩B is the intersection between two sets A and B

Given parameters

P(A)=15

P(A∪B)=1225

P(A∩B)=7100

Required

Probability of event B i.e P(B)

Using the expression above to calculate p(B), we will have;

p(A∪B) = p(A)+p(B) - p(A∩B)

1225 = 15+p(B)-7100

p(B) = 1225-15+7100

p(B) = 8310

Hence the missing probability p(B) is 8310.

You might be interested in
Find the coordinates of point Q.
Elis [28]

Answer:

Q(2, 6 )

Step-by-step explanation:

Using the midpoint formula

let the coordinates of Q = (x, y ), then

0.5(x + 10) = 6 ( multiply both sides by 2 )

x + 10 = 12 ( subtract 10 from both sides )

x = 2

and

0.5(y + 6) = 6 ( multiply both sides by 2 )

y + 6 = 12 ( subtract 6 from both sides )

y = 6

Coordinates of Q = (2, 6 )

6 0
3 years ago
Of 60 students, 24 students have a pet. What is the ratio of students with pets to students without pets?
frosja888 [35]

Answer

Find out the what is the ratio of students with pets to students without pets .

To prove

As given

of 60 students, 24 students have a pet.

Thus Total number of student = 60

students have pets = 24

students without  pets = 60 - 24

                                 = 36

Now  ratio of students with pets to students without pets .

\frac{Student\ with\ pets}{Students\ without\ pets} = \frac{24}{36}

simplify the above

\frac{Student\ with\ pets}{Students\ without\ pets} = \frac{2}{3}

Therefore the  ratio of students with pets to students without pets be 2:3 .

Hence proved

4 0
3 years ago
Read 2 more answers
What Is m∠KNL?????????????????????
Sloan [31]
U have some vertical angles....vertical angles are equal

5x + 2 = 3(x + 14)
5x + 2 = 3x + 42
5x - 3x = 42 - 2
2x = 40
x = 40/2
x = 20

JNM = 5x + 2.....5(20) + 2 = 102
KNL = 3(x + 14).....3(20 + 14)....3(34) = 102 <===

7 0
3 years ago
Solve 7ax + 8ax = 9 ax + 6 for x. Assume a ≠0.
marysya [2.9K]

The answer is B (1/a)

4 0
3 years ago
An empty box is shaped like a rectangular prism. The box has a base area of io square foot and a helght of 3 foot. How much pack
charle [14.2K]

Answer:Multiply the base area times the height to find the volume, which is the amount of packing material required

Step-by-step explanation:   example :An empty box is shaped like a rectangular prism. The box has a base area of `9/10` square foot and a height of `1/3` foot. How much packing material is required to fill the box?

First, multiply the numerators, or the top numbers. 9 * 1 = 9

Then, multiply the denominators, or the bottom numbers. 10 * 3 = 30

So, the amount of packing material required is 9/30 cubic feet.

4 0
3 years ago
Other questions:
  • X + y = k
    14·1 answer
  • Ming throws a stone off a bridge into a river below.
    12·1 answer
  • Help!!!!!!! solve the inequality
    9·1 answer
  • What is the volume of this sphere,<br> with a radius of 4 inches, to the<br> nearest tenth?
    6·1 answer
  • Help Urgent!
    7·2 answers
  • Marking brainliest <br><br><br> Pls help
    5·1 answer
  • What is the value of the slope of a line that is perpendicular to y= 1/2x +8
    15·1 answer
  • Select the correct answer.
    14·1 answer
  • Please help solve !!
    11·1 answer
  • What is an equation of the line that passes through the points (5,-6) and (-5,-4)??
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!