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Zinaida [17]
3 years ago
15

X-8=17 plssssss help me

Mathematics
2 answers:
tester [92]3 years ago
8 0
X -8 = 17
x = 17+8
x = 25
harina [27]3 years ago
7 0

Answer:

25

Step-by-step explanation:

17+8

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When you multiply a fraction with a mix number will the product always be greater than one
jok3333 [9.3K]
If we can find 1 contradiction then answer is no
hmm

less than one in a fraction is when in form a/b, b>a

1/1000 times 1 and 1/2 same as 1/1000 times 3/2=3/2000
that is less than 1

answer is NO

4 0
3 years ago
How do i find the scale factor?
AnnyKZ [126]

Answer:

1:3.7

Step-by-step explanation:

1331/27

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8 0
3 years ago
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
Plz help me with these two questions I have no idea how to do this
viktelen [127]
(7-3+4^3/2) / (9-5)
7-3+64/2) / 4
(7-3 + 32) / 4
(4 + 32) / 4
36/4 = 9

48 + 72
24(2 + 3)

8 0
4 years ago
Solve by substitution 3x+y=3 and 7x+2y=1
balu736 [363]

3x + y = 3

7x + 2y = 1

First isolate one of the variables (x or y) in one of the equations.

Isolate "y" in the first equation(because it is the easiest to isolate) and substitute it into the second equation.

3x + y = 3      Subtract 3x on both sides

3x - 3x + y = 3 - 3x

y = 3 - 3x


7x + 2y = 1

7x + 2(3 - 3x) = 1     [since y = 3 - 3x, you can substitute (3-3x) for "y"]

Multiply/distribute 2 into (3 - 3x)

7x + (3(2) - 3x(2)) = 1

7x + 6 - 6x = 1

x + 6 = 1     Subtract 6 on both sides

x = -5


Now that you know "x", substitute it into one of the equations (I will do both)

3x + y = 3

3(-5) + y = 3       [since x = -5, you can plug in -5 for "x"]

-15 + y = 3    Add 15 on both sides

y = 18


7x + 2y = 1

7(-5) + 2y = 1

-35 + 2y = 1     Add 35 on both sides

2y = 36     Divide 2 on both sides

y = 18


x = -5, y = 18  or  (-5, 18)

5 0
3 years ago
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