Complete the equation ,287x6=25, 2

3. Sophie and Jackie each have a collection of baseball cards, Jackie has 5 more cards than

IRISSAK [1]

Answer:

Sophie has 12.5 cards

Step-by-step explanation:

Let

x -----> number of cards Sophie has

y -----> number of cards Jackie has

we know that

x+y=30 -----> equation A

y=x+5 -----> equation B

Solve by substitution

Substitute equation B in equation A and solve for x

x+(x+5)=30

2x=30-5

x=12.5 cards

Note I assume the problem was invented without taking into account the result, because the amount of cards should be a whole number

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=55%20%5Cfrac%7B6%7D%7B9%3F%7D%20%20%5Ctimes%2066%20%5Cfrac%7B5%7D%7B6%7D%20" id="TexFormula1"

JulsSmile [24]

Answer:

Step-by-step explanation:

If you can present a problem in Latex, you can do anything. I don't know what the question mark is for. I'm just ignoring it.

55 2/3 * 66 5/6

One of the ways to get the answer is to use decimals

55.666666667 * 66.833333333 = 3720.38889

Another way to do this problem is to break up one of the numbers

55 2/3 (66 + 5/6) You can do this if you know how to use the distributive property.

55 2/3 * 66 + 55 2/3 * 5/6

( (165 + 2) / 3) * 66 + (165 + 2)/3 * 5/6

167/3 * 66 + 167 / 3 * 5/6

167 * 22 + (167 * 5 / (3 * 6)

3674 + 835 / 18

3674 + 46 7/18

3720 7/18

If none of these seem right and you have choices, please list them.

6 0

3 years ago

A genetics experiment involves a population of fruit flies consisting of 1 male named Bart and 3 females named Charlene, Diana,

kenny6666 [7]

Answer:

(b) $\frac{1}{2}$

Step-by-step explanation:

1 male named Bart (b)

3 females named Charlene(c), Diana(d), and Erin(e).

Since there is replacement, the possible samples are:

bb, bc, be, bd, cb, cc, cd, ce, db, dc, dd, de, eb, ec, ed, and ee.

Total Number of pairs = 16

Event of picking 2 males:bb

Event of 1 male:bc,cb,bd,db,be,eb

Event of picking 0 males:

cc, cd, ce, dc, dd, de, ec, ed, and ee.

$\begin{equation*} \begin{matrix}Proportion of males & Probability \\0 & 9/16 \\1 & 6/16 \\2 & 1/16 \end{matrix} \end{equation*}$

b. The mean of the sampling distribution

$\mu = (\frac{9}{16} X0 ) +(\frac{6}{16} X 1)+(\frac{1}{16} X 2) = \frac{8}{16} = \frac{1}{2}$

c. No; the proportion of males is $\frac{1}{4}$ while the mean is $\frac{1}{2}$ .

B. No, the sample mean is not equal to the population proportion of males. These values are not always equal, because proportion is an unbiased estimator.

7 0

2 years ago

Write a function rule for the volume of a cylinder with a height 5 cm. less than twice the radius of the cylinder's base.

n200080 [17]

Answer:

xisans

Step-by-step explanation:

ty z×ynrkkkdiod

7 0

3 years ago

The mean electric bill for Family C is approximately

Nata [24]

Do you have a picture to show, so that I can help?

8 0

3 years ago