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butalik [34]
3 years ago
12

Si se desea construir un circuito con poca resistencia se debe colocar: En serie Mixto Paralelo Ninguna de las anteriores

Physics
1 answer:
BigorU [14]3 years ago
5 0

Answer:

Parallel combination

Explanation:

When the two resistances are connected in parallel then the equivalent resistance is

\frac{1}{R}=\frac{1}{R'}+\frac{1}{R''}

To get the minimum resistance of a circuit, the circuit components should be connected in parallel combination.

In the parallel combination, the voltage across each resistor is same and the current is divided in every resistance according to the resistances.

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skad [1K]
it's joules per gram degree celsius
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4 years ago
A girl of mass 50.6 kg stands on the edge of a frictionless merry-go-round of mass 827 kg and radius 3.72 m that is not moving.
GaryK [48]

Answer:

(a). The value of angular speed of the merry-go-round \omega = - 5.82 × 10^{-3} \frac{rad}{s}

(b). The linear speed of the girl after the rock is thrown V = -1.89 × 10^{-2} \frac{m}{s}

Explanation:

Given data

Mass of the girl m_{g} = 50.6 kg

Mass of merry-go-round m_{m} = 827 kg

Radius r = 3.72 m

The speed of the rock relative to the ground V_{r} = 7.82 \frac{m}{s}

(a). The angular speed of the merry-go-round is given by

\omega = - [\frac{m_{r}v_{r}  }{r} ] \frac{2}{m_{m} + 2m_{g} }

Put all the values in above formula

\omega = \frac{(1.13)(7.82)}{3.27} \frac{2}{827 + (2)50.6}

\omega = - 5.82 × 10^{-3} \frac{rad}{s}

This is the value of angular speed of the merry-go-round.

(b). The liner speed of the girl is given by

⇒ V = r × \omega

⇒ V = - 3.72 × 5.82 × 10^{-3}

⇒ V = -1.89 × 10^{-2} \frac{m}{s}

This is the linear speed of the girl after the rock is thrown.

7 0
3 years ago
A body of mass 120 g is taken vertically upwards to reach the height of 5m,claculate work done
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FOLLOW ME FOR CLEARING YOUR NEXT DOUBT

3 0
4 years ago
A truck travels 2345 meters. How many kilometers is this? **1 kilometer = 1000 meters** *
lorasvet [3.4K]

Answer:

2.345 km

Explanation:

Step 1: Find conversion

1 km = 1000m

Step 2: Set up dimensional analysis

2345m(\frac{1km}{1000m} )

Step 3: Multiply and cancel out units

meters and meters cancel out.

We are left with km, which is what we want.

2345/1000 (base 10 system rules) = 2.345 km

8 0
4 years ago
Read 2 more answers
Daniel steps on the gas pedal of his car, and the engine increases its performance from zero to 2700 rpms (rotations per minute)
arlik [135]

Explanation:

The frequency of the engine is given by :

f=\dfrac{rpm}{60}

We have, the engine increases its performance from zero to 2700 rpms.

Frequency,

f=\dfrac{2700}{60}\ \text{cycles per second}\\\\f=45\ \text{cycles per second}

The time period of the engine is given by :

T = f/f

So,

T=\dfrac{1}{45}\ s\\\\T=0.023\ s

Hence, the required frequency and the period is 45 cycles/second and 0.023 seconds respectively.

7 0
3 years ago
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