it's joules per gram degree celsius
Answer:
(a). The value of angular speed of the merry-go-round
= - 5.82 ×

(b). The linear speed of the girl after the rock is thrown V = -1.89 ×

Explanation:
Given data
Mass of the girl
= 50.6 kg
Mass of merry-go-round
= 827 kg
Radius r = 3.72 m
The speed of the rock relative to the ground
= 7.82 
(a). The angular speed of the merry-go-round is given by
![\omega = - [\frac{m_{r}v_{r} }{r} ] \frac{2}{m_{m} + 2m_{g} }](https://tex.z-dn.net/?f=%5Comega%20%3D%20-%20%5B%5Cfrac%7Bm_%7Br%7Dv_%7Br%7D%20%20%7D%7Br%7D%20%5D%20%5Cfrac%7B2%7D%7Bm_%7Bm%7D%20%2B%202m_%7Bg%7D%20%7D)
Put all the values in above formula

= - 5.82 ×

This is the value of angular speed of the merry-go-round.
(b). The liner speed of the girl is given by
⇒ V = r × 
⇒ V = - 3.72 × 5.82 × 
⇒ V = -1.89 ×

This is the linear speed of the girl after the rock is thrown.
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Answer:
2.345 km
Explanation:
Step 1: Find conversion
1 km = 1000m
Step 2: Set up dimensional analysis

Step 3: Multiply and cancel out units
meters and meters cancel out.
We are left with km, which is what we want.
2345/1000 (base 10 system rules) = 2.345 km
Explanation:
The frequency of the engine is given by :

We have, the engine increases its performance from zero to 2700 rpms.
Frequency,

The time period of the engine is given by :
T = f/f
So,

Hence, the required frequency and the period is 45 cycles/second and 0.023 seconds respectively.