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Marianna [84]
3 years ago
13

The seatbelt across your chest should have about ______ fist width of slack

Physics
1 answer:
OLEGan [10]3 years ago
7 0
The correct answer is option (c) i.e. one

<span>The seat belt across your chest should have about one fist width of the slack. Because the seat belt across your chest is required to have minimum fist width of the slack to hold the body in place and to avoid slamming of the body against the seat belt in case of a collision at high speeds. To have one fist width of the slack, makes it a safest to wear it in case of any collision. </span>
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What is the magnitude of the applied electric field inside an aluminum wire of radius 1.2 mm that carries a 3.0-a current? [ σal
galben [10]
Hello

1) First of all, since we know the radius of the wire (r=1.2~mm=0.0012~m), we can calculate its cross-sectional area
A=\pi r^2 = 3.14 \cdot (0.0012~m)^2=4.5\cdot10^{-6}~m^2

2)  Then, we can calculate the current density J inside the wire. Since we know the current, I=3~A, and the area calculated at the previous step, we have
J= \frac{I}{A}= \frac{3~A}{4.5\cdot10^{-6}~m^2} = 6.63\cdot10^5 ~A/m^2

3) Finally, we can calculate the electric field E applied to the wire. Given the conductivity \sigma=3.6\cdot10^7~ \frac{A}{Vm} of the aluminium, the electric field is given by
E= \frac{J}{\sigma}= \frac{ 6.63\cdot10^5 ~A/m^2}{3.6\cdot10^7~ \frac{A}{Vm} } = 0.018~V/m

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3 years ago
Which statement correctly describes the gravitational potential energy of the pendulum based on this diagram?
MrRa [10]
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A 2.3 kg particle-like object moves in a plane with velocity components vx = 40 m/s and vy = 75 m/s as it passes through the poi
Sonbull [250]

Answer:

(a) \overrightarrow{L}=885.5\widehat{k}

(b) \overrightarrow{L}=1046.5\widehat{k}

Explanation:

mass, m = 2.3 kg

vx = 40 m/s

vy = 75 m/s

(a) Angular momentum is given by

\overrightarrow{L}=\overrightarrow{r}\times \overrightarrow{p}

Where, p is the linear momentum and r is the position vector about which the angular momentum is calculated.

Here, \overrightarrow{r}=3\widehat{i}-4\widehat{j}

\overrightarrow{p}=m\overrightarrow{v}

\overrightarrow{p}=2.3\left ( 40\widehat{i}+75\widehat{j} \right )

\overrightarrow{p}= 92\widehat{i}+172.5\widehat{j}

So, the angular momentum

\overrightarrow{L}=\left ( 3\widehat{i}-4\widehat{j} \right )\times\left ( 92\widehat{i}+172.5\widehat{j} \right )

\overrightarrow{L}=885.5\widehat{k}

(b) Here, \overrightarrow{r}=(3+2)\widehat{i}+(-4+2)\widehat{j}

\overrightarrow{r}=5\widehat{i}-2\widehat{j}

\overrightarrow{L}=\left ( 5\widehat{i}-2\widehat{j} \right )\times\left ( 92\widehat{i}+172.5\widehat{j} \right )

\overrightarrow{L}=1046.5\widehat{k}

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These are called neap tides!

Hope this helps :)
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