Answer:
270 m
Explanation:
Given:
v₀ = 63 m/s
a = 2.8 m/s²
t = 4.0 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (63 m/s) (4.0 s) + ½ (2.8 m/s²) (4.0 s)²
Δx = 274.4 m
Rounded to two significant figures, the displacement is 270 meters.
<span>A firefighter’s protective clothing, referred to as a turnout coat, is typically constructed as an ensemble of three layers separated by air <u>gaps,</u> if that is the word you were looking for. Take a look at the photo attached below for reference. </span>
Answer:
The equation of position and time for a sound wave is
.
Explanation:
Given that,
Wavelength = 0.190 m
Maximum pressure ![\Delta P_{max}= 0.270 N/m^2](https://tex.z-dn.net/?f=%5CDelta%20P_%7Bmax%7D%3D%200.270%20N%2Fm%5E2)
We know that,
The function of position and time for a sound wave,
....(I)
We need to calculate the frequency
Using formula of frequency
![f=\dfrac{v}{\lambda}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7Bv%7D%7B%5Clambda%7D)
Put the value into the formula
![f=\dfrac{343}{0.190}](https://tex.z-dn.net/?f=f%3D%5Cdfrac%7B343%7D%7B0.190%7D)
![f=1805.2\ Hz](https://tex.z-dn.net/?f=f%3D1805.2%5C%20Hz)
We need to calculate the angular frequency
Using formula of angular frequency
![\omega =2\pi f](https://tex.z-dn.net/?f=%5Comega%20%3D2%5Cpi%20f)
Put the value into the formula
![\omega=2\pi\times1805.2](https://tex.z-dn.net/?f=%5Comega%3D2%5Cpi%5Ctimes1805.2)
![\omega=11342.40\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D11342.40%5C%20rad%2Fs)
We need to calculate the wave number
Using formula of wave number
![k = \dfrac{2\pi}{\lambda}](https://tex.z-dn.net/?f=k%20%3D%20%5Cdfrac%7B2%5Cpi%7D%7B%5Clambda%7D)
Put the value into the formula
![k=\dfrac{2\pi}{0.190}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7B2%5Cpi%7D%7B0.190%7D)
![k=33.06](https://tex.z-dn.net/?f=k%3D33.06)
Now, put the value of k and ω in the equation (I)
![\Delta p=0.270(33.06 x-11342.40 t)](https://tex.z-dn.net/?f=%5CDelta%20p%3D0.270%2833.06%20x-11342.40%20t%29)
Hence, The equation of position and time for a sound wave is
.
Answer: when a circuit is completed (it allows the flow of electrons which causes the light bulb to produce light).
Explanation:
A circuit is described as an electrical setup that is consists of a light bulb, a switch, a wire, a battery which is arranged to allow the flow of electric current. The major components of the electrical circuit includes:
--> The BATTERY which is the source of voltage to the circuit,
--> the WIRE which is the conductive path,
--> the LIGHT BULB which is the load that needs electrical power to operate and
--> the SWITCH which is the controller.
When a circuit is COMPLETED when electrons can flow from one end of a battery all the way around, through the wires, to the other end of the battery. Along its way, it will carry electrons to electrical objects that are connected to it like the light bulb and make it to produce light.
There are different types of electric circuit which are designed to create a conductive path of current or electricity. They include:
--> closed circuit
--> open circuit
--> short circuit
--> parallel circuit
--> series circuit.
Answer:
<em>Part A</em><em>:</em>
a) If the wavelength of the light is decreased the fringe spacing Δy will decrease.
<em>Part B</em><em>:</em>
b) If the spacing between the slits is decreased the fringe spacing Δy will increase.
<em>Part C</em><em>:</em>
a) If the distance to the screen is decreased the fringe spacing will decrease.
<em>Part D</em><em>:</em>
The dot in the center of fringe E is
farther from the left slit than from the right slit.
Explanation:
In the double-slit experiment there is a clear contrast between the dark and bright fringes, that indicate destructive and constructive interference respectively, in the central peak and then is less so at either side.
The position of bright fringes in the screen where the pattern is formed can be calculated with
![\vartriangle y =\frac{m \lambda L}{d}](https://tex.z-dn.net/?f=%5Cvartriangle%20y%20%3D%5Cfrac%7Bm%20%5Clambda%20L%7D%7Bd%7D%20)
![m=0,\pm 1,\pm 2,\pm 3,.....](https://tex.z-dn.net/?f=m%3D0%2C%5Cpm%201%2C%5Cpm%202%2C%5Cpm%203%2C.....)
- m is the order number.
is the wavelength of the monochromatic light.- L is the distance between the screen and the two slits.
- d is the distance between the slits.
- Part A: a) In the above equation for the position of bright fringes we can see that if the wavelength of the light
is decreased the overall effect will be that the fringes are going to be closer. That means that the fringe spacing Δy will decrease.
- Part B: b) In the above equation for the position of bright fringes we can see that if the spacing between the slits d is decreased the fringes are going to be wider apart. That means the fringe spacing Δy will increase.
- Part C: a) In the above equation we can see that if the distance to the screen L is decreased the fringes are going to be closer. That means the fringe spacing Δy will decrease.
- Part D: We are told that the central maximum is the fringe C that corresponds with m=0. That means that fringe E corresponds with the order number m=2 if we consider it to be the second maximum at the rigth of the central one. To calculate how much farther from the left slit than from the right slit is a dot located at the center of the fringe E in the screen we use the condition for constructive interference. That says that the path length difference Δr between rays coming from the left and right slit must be
We simply replace the values in that equation :
![\vartriangle r= m \lambda =2.\ 460\ nm](https://tex.z-dn.net/?f=%5Cvartriangle%20r%3D%20m%20%5Clambda%20%3D2.%5C%20460%5C%20nm)
![\vartriangle r= 920\ x\ 10^{-9} m](https://tex.z-dn.net/?f=%5Cvartriangle%20r%3D%20920%5C%20x%5C%2010%5E%7B-9%7D%20m)
The dot in the center of fringe E is
farther from the left slit than from the right slit.