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Marianna [84]
3 years ago
13

The seatbelt across your chest should have about ______ fist width of slack

Physics
1 answer:
OLEGan [10]3 years ago
7 0
The correct answer is option (c) i.e. one

<span>The seat belt across your chest should have about one fist width of the slack. Because the seat belt across your chest is required to have minimum fist width of the slack to hold the body in place and to avoid slamming of the body against the seat belt in case of a collision at high speeds. To have one fist width of the slack, makes it a safest to wear it in case of any collision. </span>
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8 points
Lunna [17]
The pilot might be correct (I think), because, if the gravity of the planet is strong, then the planet’s gravity will pull the spaceship into its orbit, so the engines don’t need to be on for the ship to get pushed toward the planet.
4 0
3 years ago
Read 2 more answers
Can you please help - the answer I got so far is 7.624 but when I enter it in my homework in Quest, it i stating that this answe
torisob [31]

Answer:

-7.04

Explanation:

9.8 multipled by -0.719 b

6 0
3 years ago
Depending on circumstances, there are times when divers may wish to be positively, negatively or neutrally buoyant. True. False.
ser-zykov [4K]

Answer:

True

Explanation:

Buoyancy is the most important factors for divers. All they do underwater is to observe the life down there but they also have some other work. However, divers may want to be negatively buoyant when they want to go on deep exploration. When they reach a destination, they may want to observe and neutral buoyancy then will be useful. When they want to go back on surface, they’ll utilize positive buoyancy.

7 0
3 years ago
Three forces are applied to a solid cylinder of mass 12 kg (see the drawing). The magnitudes of the forces are F1 = 15 N, F2 = 2
crimeas [40]

Answer:

α = 13.7 rad / s²

Explanation:

Let's use Newton's second law for rotational motion

         ∑ τ = I α

         

we will assume that the counterclockwise turns are positive

         F₁  0 + F₂ R₂ - F₃ R₃ = I α

give us the cylinder moment of inertia

        I = ½ M R₂²

         

        α = (F₂ R₂ - F₃ R₃)  \frac{2}{M R_2^2}

let's calculate

        α = (24  0.22 - 13  0.10) \frac{2}{12 \ 0.22^2}2/12 0.22²

        α = 13.7 rad / s²

6 0
3 years ago
a 5.0 charge is placed at the 0 cm mark of a meterstick and a -4.0 charge is placed at the 50 cm mark. what is the electric fiel
Lesechka [4]

Answer:

-1748*10^N/C

Explanation:

See attached file

8 0
3 years ago
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