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cupoosta [38]
3 years ago
10

During takeoff, a plane accelerates at 4 m/s and takes 40 s to reach takeoff speed. What is the velocity of the plane at takeoff

?
Physics
1 answer:
Brums [2.3K]3 years ago
3 0

Velocity = distance / time

v = d /t

    =  4ms⁻¹ / 40s

v =   0.4 ms⁻²    .

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\rm 9.186\times 10^{-7}\ C.

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  • \rm q = magnitude of the charge on each of the plate.
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\rm E = \dfrac{q}{A\epsilon_o}\\\Rightarrow q = E\ A\epsilon_o\\=3\times 10^6\times 3.46\times 10^{-2}\times 8.85\times 10^{-12}\\=9.186\times 10^{-7}\ C.

It is the maximum value of the magnitude of charge which can be added up to each of the plates of the capacitor.

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