Answer:
x^0 y^-3 / x^2 y^-1
= 1 / x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)
Answer:
Step-by-step explanation:
Given: 
To solve this equation, we need to isolate 
on one side of the equation algebraically. I see that we have like terms, but they are on opposite sides of the equal sign. Let's add 
to both sides.
To isolate x, divide both sides by 7.
Answer:
Step-by-step explanation:
I=PRT/100
I=5000*10*4=200,000/100
I=$2000
Step-by-step explanation:
= (x - 3)(2x² - 5x + 1)
= 2x³ - 5x² + x - 6x² + 15x - 3
= 2x³ + (-5 - 6)x² + (1 + 15)x - 3
= 2x³ - 11x² + 16x - 3
Option → C
