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Tatiana [17]
3 years ago
10

On a piece of paper graph y ≤ - 2x. Then determine which answer matches the graph you drew ?

Mathematics
1 answer:
nataly862011 [7]3 years ago
4 0

Answer:

hope it helps

Step-by-step explanation:

The given inequality is

The sign of inequality is ≤, it means the points on relation line lie in the solution set.

The related equation of the inequality is

At x=0,

At x=1,

Plot the points (0,0) and (1,-2) on a coordinate plane.

The sign of inequality is ≤, it means we have shade below the line.

The point (-2,4) and (3,-6) are in solution set because,

    (True)

     (True)

Therefore option A is correct.

The points (1,2) and (1,3) are not in the solution set because,

   (False)

  (False)

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Can someone help me with this math question i really don’t know how to do it!
julia-pushkina [17]

Answer:

1260

Step-by-step explanation:

He asked 180 people and 63 said cookies so I think you have to do 63 out of each 180 people so you would do 3600 ÷ 180 = 20, 20 x 63 =1260

Not sure if this is right, hope this helps

8 0
3 years ago
Some people think it is unlucky if the 13th day of month falls on a Friday. show that in that there year (non-leap or leap) ther
Vlad1618 [11]
<span>There are several ways to do this problem. One of them is to realize that there's only 14 possible calendars for any year (a year may start on any of 7 days, and a year may be either a leap year, or a non-leap year. So 7*2 = 14 possible calendars for any year). And since there's only 14 different possibilities, it's quite easy to perform an exhaustive search to prove that any year has between 1 and 3 Friday the 13ths. Let's first deal with non-leap years. Initially, I'll determine what day of the week the 13th falls for each month for a year that starts on Sunday. Jan - Friday Feb - Monday Mar - Monday Apr - Thursday May - Saturday Jun - Tuesday Jul - Thursday Aug - Sunday Sep - Wednesday Oct - Friday Nov - Monday Dec - Wednesday Now let's count how many times for each weekday, the 13th falls there. Sunday - 1 Monday - 3 Tuesday - 1 Wednesday - 2 Thursday - 2 Friday - 2 Saturday - 1 The key thing to notice is that there is that the number of times the 13th falls upon a weekday is always in the range of 1 to 3 days. And if the non-leap year were to start on any other day of the week, the numbers would simply rotate to the next days. The above list is generated for a year where January 1st falls on a Sunday. If instead it were to fall on a Monday, then the value above for Sunday would be the value for Monday. The value above for Monday would be the value for Tuesday, etc. So we've handled all possible non-leap years. Let's do that again for a leap year starting on a Sunday. We get: Jan - Friday Feb - Monday Mar - Tuesday Apr - Friday May - Sunday Jun - Wednesday Jul - Friday Aug - Monday Sep - Thursday Oct - Saturday Nov - Tuesday Dec - Thursday And the weekday totals are: Sunday - 1 Monday - 2 Tuesday - 2 Wednesday - 1 Thursday - 2 Friday - 3 Saturday - 1 And once again, for every weekday, the total is between 1 and 3. And the same argument applies for every leap year. And since we've covered both leap and non-leap years. Then we've demonstrated that for every possible year, Friday the 13th will happen at least once, and no more than 3 times.</span>
5 0
3 years ago
There were 450 people at a play. The admission price was $2 for adults and $1 for children. The admission receipts were $680. Ho
vampirchik [111]

Answer:

Adults= 110

Children= 340

Step-by-step explanation:

Given data

let adults be x

and children be y

x+y= 450----------1

2x+y=680---------2

from 1

x= 450-y

put this in 2

2(450-y)=680

900-2y=680

900-680=2y

220=2y

y= 220/2

y= 110

x+110= 450

x= 450-110

x=340

4 0
3 years ago
HURRY.. I NEED TO HAND IT IN NOW ​
Anon25 [30]

Answer:

i) 20m/s

ii) 4s

iii) 144m

iv) 2 m/s

Step-by-step explanation:

Please see attached picture for full solution.

5 0
3 years ago
What is the length of AC?
Alenkasestr [34]
So in order to find line AC you must find line AD and DC then plus them together.

to find AD use Pythagoras theorem
a^2 = c^2 - b^2
AD^2 = 7.5^2 - 6.5^2
AD^2 = 56.25 - 42.25
AD^2 = 14
square root both sides to get rid of the ^2
AD ≈ 3.7 or 3.74

Do the same for DC
DC^2 = 10^2 - 6.5^2
DC^2 = 100 - 42.25
DC^2 = 57.75
DC ≈ 7.6

now plus AD and DC which should give u 11.3
5 0
3 years ago
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